Which of the following describes an air mass with the symbol cT?
2 answers:
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Answer : 121.5 <span>μCi
Explanation : We have Ce-141 half life given as 32.5 days so if the activity is 3.8 </span><span>μci after 162.5 days of time elapsed we have to find the initial activity.
We can use this formula;
</span>
3.8 /
= 
((0.693 X 162.5 ) / 32.5) = 121.5
<span>
On solving we get, The initial activity as 121.5 </span>μci
Explanation : We have Ce-141 half life given as 32.5 days so if the activity is 3.8 </span><span>μci after 162.5 days of time elapsed we have to find the initial activity.
We can use this formula;
</span>
3.8 /
<span>
On solving we get, The initial activity as 121.5 </span>μci
Answer: The final temperature of both the weight and the water at thermal equilibrium is .
Explanation:
The given data is as follows.
mass = 7.62 g,
Let us assume that T be the final temperature. Therefore, heat lost by water is calculated as follows.
q =
=
Now, heat gained by lead will be calculated as follows.
q =
=
According to the given situation,
Heat lost = Heat gained
=
T =
Thus, we can conclude that the final temperature of both the weight and the water at thermal equilibrium is .