It is eight times more than the star A.
<h3>What is luminosity and on which it depends?</h3>
The luminosity of an object is a measure of its intrinsic brightness and is defined as the amount of energy the object emits in a fixed time.
luminousity depends upon the two factors are:
1) The star's actual brightness
Some stars are naturally more luminous than others ,so the brightness level from one star to next star is significantly different.
2) The star distance from us
The more distance of an object the dimmer it appears.
Energy emitted = sAT⁴
where s is stefan constant
A is surface area and T is temperature .
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Answer:
Opposite to the direction that you are pulling
Explanation:
Static friction acts in the opposite direction to the acceleration.
Kinetic friction acts in the opposite direction to the velocity.
Answer:
The answer to your question is va = 8 cm/s, vb = 12.5 cm/s, a = 9 cm/s²
Explanation:
Data
Ta = 0.125 s
Tb = 0.08 s
Δtab = 0.5 s
distance = 1 cm
Process
1.- Calculate va
va = 1/0.125 = 8 cm/s
vb = 1/0.08 = 12.5 cm/s
2.- Calculate Δv
Δv = 12.5 - 8
Δv = 4.5 cm/s
3.- Calculate acceleration
a = Δv / Δt
a = 4.5/0.5
a = 9 cm/s²
Answer:
a) a = 34.375 m / s², b) v_f = 550 m / s
Explanation:
This problem is the launch of projectiles, they tell us to ignore the effect of the friction force.
a) Let's start with the final part of the movement, which is carried out from t= 16 s with constant speed
v_f =
we substitute the values
v_f =
The initial part of the movement is carried out with acceleration
v_f = v₀ + a t
x₁ = x₀ + v₀ t + ½ a t²
the rocket starts from rest v₀ = 0 with an initial height x₀ = 0
x₁ = ½ a t²
v_f = a t
we substitute the values
x₁ = 1/2 a 16²
x₁ = 128 a
v_f = 16 a
let's write our system of equations
v_f =
x₁ = 128 a
v_f = 16 a
we substitute in the first equation
16 a =
16 4 a = 6600 - 128 a
a (64 + 128) = 6600
a = 6600/192
a = 34.375 m / s²
b) let's find the time to reach this height
x = ½ to t²
t² = 2y / a
t² = 2 5100 / 34.375
t² = 296.72
t = 17.2 s
We can see that for this time the acceleration is zero, so the rocket is in the constant velocity part
v_f = 16 a
v_f = 16 34.375
v_f = 550 m / s