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____ [38]
2 years ago
10

What are the sign and magnitude in coulombs of a point charge that produces a potential of -3.50 V at a distance of 2.00 mm

Physics
1 answer:
DanielleElmas [232]2 years ago
5 0

The magnitude and sign of the charge are 0.8 MC and negative respectively.

To find the answer, we need to know about the electric potential of a point charge.

<h3>What's the mathematical expression of the electric potential of a point charge?</h3>
  • Mathematically, the electric potential at a distance 'r' from a point charge 'q' is given as (Kq)/r.
  • K is the electrical constant with value 9×10^(-9) in vaccum.
<h3>What will be the magnitude and sign of a charge, if potential is -3.50V at 2mm?</h3>

From the expression of electric potential, charge is

q= (potential ×r)/K

= (-3.5×0.002)/ (9×10^(-9))

= -0.8 mega coulomb.

Thus, we can conclude that the magnitude and sign of the charge are 0.8 MC and negative respectively.

Learn more about the electric potential here:

brainly.com/question/14306881

#SPJ4

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A jetliner flies at a constant speed covering 467 miles in 3.3 hours. What is the speed of the plane in miles per hour?
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A meter stick is suspended vertically at a pivot point 22 cm from the top end. It is rotated on the pivot until it is horizontal
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Answer:

5.82812 rad/s

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\omega = Angular velocity

Moment of inertia of the system is given by

I=I_c+mr^2\\\Rightarrow I=\frac{mL^2}{12}+mr^2\\\Rightarrow I=\frac{m1^2}{12}+m0.28^2\\\Rightarrow I=m(\frac{1}{12}+0.0784)

As the energy in the system is conserved

mgh=I\frac{\omega^2}{2}\\\Rightarrow mgh=m(\frac{1}{12}+0.0784)\frac{\omega^2}{2}\\\Rightarrow gh=(\frac{1}{12}+0.0784)\frac{\omega^2}{2}\\\Rightarrow \omega=\sqrt{\frac{2gh}{\frac{1}{12}+0.0784}}\\\Rightarrow \omega=\sqrt{\frac{2\times 9.81\times 0.28}{\frac{1}{12}+0.0784}}\\\Rightarrow \omega=5.82812\ rad/s

The maximum angular velocity is 5.82812 rad/s

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