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____ [38]
1 year ago
10

What are the sign and magnitude in coulombs of a point charge that produces a potential of -3.50 V at a distance of 2.00 mm

Physics
1 answer:
DanielleElmas [232]1 year ago
5 0

The magnitude and sign of the charge are 0.8 MC and negative respectively.

To find the answer, we need to know about the electric potential of a point charge.

<h3>What's the mathematical expression of the electric potential of a point charge?</h3>
  • Mathematically, the electric potential at a distance 'r' from a point charge 'q' is given as (Kq)/r.
  • K is the electrical constant with value 9×10^(-9) in vaccum.
<h3>What will be the magnitude and sign of a charge, if potential is -3.50V at 2mm?</h3>

From the expression of electric potential, charge is

q= (potential ×r)/K

= (-3.5×0.002)/ (9×10^(-9))

= -0.8 mega coulomb.

Thus, we can conclude that the magnitude and sign of the charge are 0.8 MC and negative respectively.

Learn more about the electric potential here:

brainly.com/question/14306881

#SPJ4

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Answer:

0.07756 m

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Given mass of object =0.20 kg

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So v_{max}=A\sqrt{\frac{k}{m}}

A=V_{max}\sqrt{\frac{m}{k}}=1.9\times \sqrt{\frac{0.2}{120}}=0.07756 \ m

3 0
3 years ago
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ipn [44]
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fenix001 [56]

Answer:

3.5m/s^2

Explanation:

From Newton's second Law of Motion

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Explanation:

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