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2 years ago

What causes air to rise in the equator

Chemistry

1 answer:

Serjik [45]2 years ago

5 0

The Sun heats the Earth more at the equator

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Which is a diatomic molecule? A)He B)O2 C) NaCl D)CuF2

katrin2010 [14]

Answer:

B. O2

Explanation:

3 0

3 years ago

Read 2 more answers

Which cell structures does this fish embryo cell contain? Select all that apply.

Katyanochek1 [597]

Answer:

Nucleus,mitochondria,& cell membrane

6 0

3 years ago

Write the full ground state electron configuration of C − C− . electron configuration: Which neutral atom is isoelectronic with

stepan [7]

Answer: 1. Is2 2s2 2p3

2. Nitrogen

Explanation: The number of electron present In C = 6

But an extra electron is added since the charge on C is -1, this therefore makes the total electron 7.

1. By arrangement, the Electronic configuration is therefore;

Ans: 1s2 2s2 2p3

2. It is explained how C has 7 electrons, we can proceed then.

Neutral atom have atomic number of 7.

The element with atomic number of 7 is;

Ans: NITROGEN

7 0

3 years ago

What number of electrons balances the charges in this half reaction

Digiron [165]

Answer : Two electrons balances the charges in this half reaction.

Explanation :

The given half reaction is,

$SO_2+2H_2O\rightarrow SO^{2-}_4+4H^+$

In this half reaction, there is no charges present on the left side of the reaction but on right side of the reaction, (2+) charge is present. So, two electrons (2-) are added on the right side of the reaction for balances the charge of the half reaction.

The balanced half reaction is,

$SO_2+2H_2O\rightarrow SO^{2-}_4+4H^++2e^-$

Hence, two electrons balances the charges in this half reaction.

6 0

3 years ago

How many joules of heat are needed to raise the temperature of 30.0 g of aluminum from 22°C to 80°C, if the specific heat of alu

USPshnik [31]

Answer: There are 1566 joules of heat needed to raise the temperature of 30.0 g of aluminum from 22°C to 80°C, if the specific heat of aluminum is 0.90 J/g°C.

Explanation:

Given: Mass = 30.0 g

Specific heat = $0.90 J/g^{o}C$

$T_{1} = 22^{o}C$

$T_{2} = 80^{o}C$

Formula used to calculate the heat energy requires is as follows.

$q = m \times C \times (T_{2} - T_{1})$

where,

q = heat energy

m = mass of substance

C = specific heat capacity of substance

$T_{1}$ = initial temperature

$T_{2}$ = final temperature

Substitute the values into above formula as follows.

$q = m \times C \times (T_{2} - T_{1})\\= 30.0 g \times 0.90 J/g^{o}C \times (80 - 22)^{o}C\\= 1566 J$

Thus, we can conclude that there are 1566 joules of heat needed to raise the temperature of 30.0 g of aluminum from 22°C to 80°C, if the specific heat of aluminum is 0.90 J/g°C.

6 0

2 years ago