Question

100 points! Formation of an Ion

Answer 1

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If every oxygen ion is combined with an aluminium ion has a charge of -2,the charge of each aluminum ion would be -3.

Uncharged Aluminum atom must need to lose it's electrons,in order to form the bond with oxygen which has vacant orbitals


ion

atom that has a positive or negative charge because it lost or gained one or more electrons

chemical bond

the attractive force that holds atoms or ions together

ionic bond

a chemical bond in which one atom loses an electron and the other atom gains electrons to form ions

chemical formula

a combination of chemical symbols and numbers to represent a substance

covalent bond

bond formed by the sharing of electrons between atoms

Answer 2

What you have to realize is who is creating the charge and who is receiving it.

Oxygen and Aluminum  are in their ionic form. Ions are produced by electron movement.

Aluminum gives away electrons (3 of them).

Oxygen takes on electrons (2 of them).

The 2 and the 3 in Al2O3 tells you how many electrons were given up and how they were taken on.

The 2 and the 3 in Al2O3 also tells you (indirectly) what the lowest common denominator is.

So once you understand the above 2 sentences you will understand the answer to your questions.

The lowest common multiple of 3 and 2 is six.

If the Aluminum gives up 3 electrons per atom, then to get to 6, you will have to have two aluminums.

If oxygen takes on 2 electrons then to get to six. There must be 3 oxygens present. Look at the formula

Al2 there are two aluminums

O3 there are three oxygens. That's why the formula is written the way it is.

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Aluminum is never seen alone because it is very eager to give up it's 3 electrons. It will combine with almost anything that is willing to receive those electrons.

Compare it to gold. Gold will combine with almost nothing ionically. Separating gold from a none metal won't happen normally, and refining to get rid of that problem just won't occur.