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blondinia [14]
2 years ago
9

A molecular property of the Group 6A(16) hydrides changes abruptly down the group. This change has been explained in terms of a

change in orbital hybridization.(d) What other group displays a similar change?
Chemistry
1 answer:
Novay_Z [31]2 years ago
6 0

A molecular property of the Group 6A(16) hydrides changes abruptly down the group. This change has been explained in terms of a change in orbital hybridization can see a similar difference in Group 15 as well where the same thing influences stability through bond strength (decrease in bond dissociation enthalpy down the group).

We can see a similar difference in Group 15 as well where the same thing influences stability through bond strength (decrease in bond dissociation enthalpy down the group). The change is a significant decrease in \textbf{bond angle}bond angle. Down the group we're observing increase in size as well as decrease in electronegativity which causes position of bond pairs of electrons to shift more and more away from the central atom. That then causes a decrease in repulsion between bonded pairs which results in a decrease in bond angle hydrides.

Learn more about hydrides on:
brainly.com/question/8376431

#SPJ4

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The concentration of the Nitric acid solution : 0.114 M

<h3>Further explanation  </h3>

Titration is a procedure for determining the concentration of a solution (analyte) by reacting with another solution whose known concentration (usually a standard solution) is called the titrant. Determination of the endpoint/equivalence point of the reaction can use indicators according to the appropriate pH range  

Titrations can be acid-base titration, depositional titration, and redox titration. An acid-base titration is the principle of neutralization of acids and bases  

Reaction

HNO₃ + NaOH → NaNO₃ + H₂O​

Concentration a standard solution  of sodium hydroxide :  0.0998 mol/dm³ , and the volume = 25 cm³

moles NaOH=

\tt mol=M\times V\\\\mol=0.0998\times 25\\\\mol=2.495~mlmoles

<em>From the equation, mol ratio HNO₃ : NaOH = 1 : 1, so mol HNO₃ = mol NaOH=</em><em>2.495 mlmoles</em>

<em></em>

The volume of HNO₃ = 21.8 cm³, so the concentration :

\tt M=\dfrac{n}{V}\\\\M=\dfrac{2.495}{21.8}\\\\M=0.114

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How many mols are present in the a sample of silver nitrate which has<br> 5.3x10^24 molecules.
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Answer:  5.3 x 10^24 formula units of silver nitrate is equivalent to 8.8 moles of silver nitrate. Silver nitrate is an ionic compound, therefore, its representative particle is called a "formula unit" instead of molecule. For every mole of a substance, we know that there are 6.022 x 10^23 representative units of that substance. The amount of particles in one mole of substance is called Avogadro's number.

Further Explanation:

We can convert from number of representative particles to moles using the formula:

\boxed {no. \ of \ moles \ = \ ( given \ no. \ of \ particles) \ (\frac{1 \ mole}{\ 6.022 \ x 10^{23} particles})}

For this problem, we can calculate the number of moles by plugging in the given values to the equation above,

no. \ of \ moles \ = (5.3 \ x \ 10^{24} \ formula \ units \ AgNO_{3}) \ (\frac{1 \ mole \ AgNO_{3}}{6.022 \ x 10^{23} \ formula \ units AgNO_{3}}) \\\\\boxed {no. \ of moles \ AgNO_{3} \ = \ 8.8 \ moles}

Learn More

  1. Learn more about representative particles brainly.com/question/8969313
  2. Learn more about Avogadro's number brainly.com/question/229300
  3. Learn more about mole conversions brainly.com/question/1370888

Keywords: moles conversion, Avogadro's number

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