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3 years ago

Which scientist provided a foundation for John Dalton’s work on the atomic structure?

Chemistry

1 answer:

zhenek [66]3 years ago

7 0

Joseph Proust is the scientist who provided a foundation for John Dalton's work on the atomic structure.

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Which Statements below are true?

yKpoI14uk [10]

A. If motion starts and stops at the same location, then the displacment is zero.

D. Distance is always greater than or equal to the magnitutde of the displacement.

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3 years ago

What would happen to the block if it had a density of 0.500 kg/L and was placed in the same 100.0 L tank of water?

raketka [301]

I’m not sure if there was important information in the question before this one, but the answer based on the info I have is B.

The density of water is 1kg/L. Since the density of the block is less, it will float.

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3 years ago

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Determine the mass of MgCl2 needed to create a 100. ml solution with a concentration of 3.00 M.

kiruha [24]

Explanation:

$1000ml \: contain \: 3 \: moles \\ 100 \: ml \: will \: contain \: ( \frac{100 \times 3}{1000} ) \: moles \\ = 0.3 \: moles \\ RFM = 95 \\ 1 \: mole \: weighs \: 95 \: g \\ 0.3 \: moles \: weigh \: ( \frac{(0.3 \times 95)}{1} \: g \\ = 28.5 \: g \: of \: magnesium \: chloride$

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3 years ago

How do you calculate atomic number

kifflom [539]

The number of protons in the nucleus of an atom is equal to the atomic number of an element. You can also find it by subtracting the number of neutrons from the atomic mass. Atomic Number = Atomic Mass - No. of Neutrons.

4 0

4 years ago

At standard ambient temperature and pressure (SATP), a gas has density of 1.5328g/L. What is the molar mass of the gas?

ahrayia [7]

The standard ambient temperature and pressure are

Temperature =298 K

Pressure = 1atm

The density of gas is 1.5328 g/L

density = mass of gas per unit volume

the ideal gas equation is

PV = nRT

P = pressure = 1 atm

V = volume

n = moles

R= gas constant = 0.0821 Latm/mol K

T = 298 K

moles = mass / molar mass

so we can write

n/V = density / molar mass

Putting values

$Pressure=\frac{nRT}{V}=\frac{massXRT}{VXmolarmass}$

$Pressure=\frac{densityXRT}{molarmass}$

$molarmass=\frac{densityXRT}{Pressure}=\frac{1.5328X0.0821X298}{1}=37.50$

Thus molar mass of gas is 37.50g/mol

6 0

4 years ago