Answer:
The coefficient of rolling friction for the tire under low pressure is 0.0342.
Explanation:
Two bicycle tires are set rolling with the same initial speed of 4.00 m/s
Final speed of both the bicycle, speed is reduced by half is measured, v = 2 m/s.
Here,
Using third equation of motion as :
So, the coefficient of rolling friction for the tire under low pressure is 0.0342.
A is 588N.
b) When she reaches her terminal speed, 10 seconds into the dive, she is no longer accelerating, so the net force on her is zero.
Think of it this way: If the net force were not zero she would continue to accelerate.
c) She is no longer accelerating.
Her acceleration is zero.
75 percent (calculated percentage %) of what number equals 27? Answer: 36.
To present your findings/data
