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Answer:
= 308.5 N
Explanation:
acceleration of rocket for safe landing
= initial velocity
=final Velocity
m = mass of rocket
-5.625 
Upward force
F - mg = ma
F = ma+ mg
F = m(a+g)
m= mass
a = 5.625
g = 9.8
= 20(5.625 + 9.8)
= 308.5 N
Answer:
The force of the ball on the bat is same as the force of the bat on the ball.
Explanation:
A bat hits the ball and the ball moves to the out filed.
According to the Newton's third law, for every action there is an equal and opposite reaction.
The action and the reaction forces acts on the two different bodies but the magnitude of the force is same.
As the ball is hitted by the bat, the bat exerts the force on the ball and the same force is exerted on the bat by the ball according to the Newton's third law.
So, the force of the ball on the bat is same as the force of the bat on the ball but the direction of force is opposite.
Answer:
Option B. 6.25 J/S
Explanation:
Data obtained from the question include:
t (time) = 2secs
F (force) = 50N
d (distance) = 0.25m
P (power) =?
The power can be obtained by using the formula P = workdone/time.
P = workdone / time
P = (50 x 0.25)/ 2
P = 6.25J/s
Answer:
v_f = 30 m/s
Explanation:
v_f = v_I + a*t
v_f = 0m/s + (9.81m/s²)*(3s)
v_f = 29.43m/s
v_f = 30 m/s
Since the object is being launched horizontally off the cliff the only vertical force acting on the ball is gravity which is an acceleration of 9.81m/s². So we have all the flowing information to use the the kinematic equation: v_f = v_I + a*t.
