All categories

2 years ago

In terms of numbers of reactant and product substances, which organic reaction type corresponds to (b) a decomposition reaction,

1 answer:

7 0

In terms of numbers of reactant and product substances, decomposition reaction is a organic reaction type corresponds.

<h3>What is decomposition reaction?</h3>

A chemical breaking down into two or more simpler compounds is known as a decomposition process. A decomposition reaction has the general form AB→A+B Energy input in the form of heat, light, or electricity is necessary for the majority of decomposition reactions.

Examples of decomposition reactions

• CaCO3(s) → CaO(s) + CO2(g)

• The breakdown of hydrogen peroxide to water and oxygen, and the breakdown of water to hydrogen and oxygen.

Decomposition reactions can take a variety of forms.

Thermal ones.
Heat-induced chemical reaction when one material splits into two or more compounds.
Reaction of Electrolytic Decomposition.
Reaction to Photo Decomposition.

To know more about Decomposition reaction please click here : brainly.com/question/27300160

#SPJ4

You might be interested in

What did Aristotle believe?

Crank

Answer:

C.) That all matter was composed of earth, fire, water and air

Explanation:

Just took the test

4 0

3 years ago

Use bond energies to calculate the enthalpy of reaction for the combustion of ethane. Average bond energies in kJ/mol C-C 347, C

ivanzaharov [21]

The enthalpy of reaction for the combustion of ethane 2CH₃CH₃ + 7O₂ → 4CO₂ + 6H₂O calculated from the average bond energies of the compounds is -2860 kJ/mol.

The reaction is:

2CH₃CH₃ + 7O₂ → 4CO₂ + 6H₂O (1)

The enthalpy of reaction (1) is given by:

$\Delta H = \Delta H_{r} - \Delta H_{p}$ (2)

Where:

r: is for reactants

p: is for products

The bonds of the compounds of reaction (1) are:

2CH₃CH₃: 2 moles of 6 C-H bonds + 2 moles of 1 C-C bond

7O₂: 7 moles of 1 O=O bond

4CO₂: 4 moles of 2 C=O bonds

6H₂O: 6 moles of 2 H-O bonds

Hence, the enthalpy of reaction (1) is (eq 2):

$\Delta H = \Delta H_{r} - \Delta H_{p}$

$\Delta H = 2*\Delta H_{CH_{3}CH_{3}} + 7\Delta H_{O_{2}} - (4*\Delta H_{CO_{2}} + 6*\Delta H_{H_{2}O})$

$\Delta H = 2*(6*\Delta H_{C-H} + \Delta H_{C-C}) + 7\Delta H_{O=O} - (4*2*\Delta H_{C=O} + 6*2*\Delta H_{H-O})$

$\Delta H = [2*(6*413 + 347) + 7*498 - (4*2*799 + 6*2*467)] kJ/mol$

$\Delta H = -2860 kJ/mol$

Therefore, the enthalpy of reaction for the combustion of ethane is -2860 kJ/mol.

I hope it helps you!

7 0

3 years ago

What is the volume, in liters, of 2.00 moles of hydrogen at STP?

Ber [7]

The volume of one mole of any gas at STP is 22.4 L. So, at STP, the volume of 2.00 moles of hydrogen gas would be (22.4 L/mol)(2 mol H2) = 44.8 L.

8 0

3 years ago

What do radio waves and gamma rays have in common?

padilas [110]

Answer: The sequence from longest wavelength (radio waves) to shortest wavelength (gamma rays) is also a sequence in energy from lowest energy to highest energy. ... The energy carried by a radio wave is low, while the energy carried by a gamma ray is high. Different materials can block different types of light.

PLEASE MARK BRAINLIEST

5 0

3 years ago

Read 2 more answers

A 0.75M solution of CH3OH is prepared in 0.500 kg of water. How many moles of CH3OH are needed?

4vir4ik [10]

Answer:

We need 0.375 mol of CH3OH to prepare the solution

Explanation:

For the problem they give us the following data:

Solution concentration 0,75 M

Mass of Solvent is 0,5Kg