Group 7
Explanation:
The unknown element belongs to the seventh group on the periodic table of elements.
Ionic bonds are usually formed between metals and nonmetals. They formed by the transfer of electrons from the less electronegative specie to the more electronegative one.
The metals usually lose electron because they are highly electropositive species.
- If we have a magnesium atom with two valence electrons.
- To form ionic bonds, it must transfer the two electrons to another atom.
- The other atom, a nonmetal must be ready to accommodate and receive the donated electrons.
- This ensure that its own octet is complete.
- Group 6 elements requires 2 electrons to have a complete octet.
- They can receive the two electrons
But we were told that there are two atoms of that element for each of the magnesium atom;
the atom must have a capacity of collecting one electron each to be stable.
Such atoms are found in Group 7 on the periodic table.
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Answer:
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Answer:
OH⁻(aq) + NH₄⁺(aq) → NH₃(g) + H₂O(l)
Explanation:
The net ionic equation is a way yo write a chemical equation that list only the species that are involved in the reaction.
For the reaction:
NaOH(aq) + NH₄Br(aq) → NaBr(aq) + NH₃(g) + H₂O(l)
Ionic equation is:
Na⁺(aq) + OH⁻(aq) + NH₄⁺(aq) + Br⁻(aq) → Na⁺(aq) + Br⁻(aq) + NH₃(g) + H₂O(l)
<em>-Ions comes from the species that are in aqueous phase-</em>
And net ionic equation is:
<em>OH⁻(aq) + NH₄⁺(aq) → NH₃(g) + H₂O(l)</em>
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Answer:

Explanation:
The formula for molality is:

There are 0.210 moles of KBr and 0.075 kilograms of pure water.

Substitute the values into the formula.

Divide.

The molality is <u>2.8 moles per kilogram</u>
Answer:
N-1
Explanation:
All nitrogen positions in purine rings (N-1, N-3, N-7 and N-9) have the potential to form hydrogen bonds. Among them, only N-1 is involved in Watson-Crick base pairing hydrogen bond with a pyridimine. N-3 and N-7 are available to form further hydrogen bonds and N-9 is involved in a N-glycosyl linkage with a desoxyribose.