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Hitman42 [59]
3 years ago
15

What is the end result of a nuclear fusion reaction? two new atoms with smaller nuclei form molecule of atoms forms one new atom

with a larger nucleus forms new bonds between atoms are formed
Chemistry
2 answers:
Arlecino [84]3 years ago
7 0

Answer: Option (c) is the correct answer.

Explanation:

When two small or light atomic nuclei combine together then it results in the formation of a larger nuclei.This process is known as nuclear fusion.

For example, ^{2}_{1}H + ^{3}_{1}H \rightarrow ^{4}_{2}He + ^{1}_{0}n + Energy

Whereas when a larger atomic nuclei splits into two small atomic nuclei then it is known as a nuclear fission.

For example, ^{235}_{92}U + ^{1}_{0}n \rightarrow ^{90}_{36}Kr + ^{143}_{56}Ba + 3^{1}_{0}n

Thus, we can conclude that the end result of a nuclear fusion reaction is one new atom with a larger nucleus.

Mashutka [201]3 years ago
6 0
The end result of a nuclear fusion reaction is one new atom with a larger nucleus.Nuclear fusion is a reaction in which two or more atomic nuclei come close enough to form one or more different atomic nuclei and sub atomic particles. Fusion of light elements toward these releases energy, while fusion producing nuclei heavier than these elements will result in energy retained by the resulting nucleons, and the resulting reaction is endothermic.
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Hi. Increased evaporation would be the greatest difference.

Explanation:

Have you ever had a drink in a mug with a lid? When you would remove the lid, all of the liquid on the lid is the liquid that would evaporate if there was no lid.

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2 years ago
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9. To become like a noble gas the element P will have a charge of
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Water vapor condenses into a glass of water. The water is then placed in a freezer and changes into ice. What remains consistent
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Suppose 180 ml of 3.52x10^-4 M NaOH is mixed with 220 mL of 2.47x10^-4 M MgCl2.
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3 years ago
Be sure to answer all parts. A concentration cell consists of two Sn/Sn2+ half-cells. The electrolyte in compartment A is 0.23 M
kolbaska11 [484]

Answer:

Part A. The half-cell B is the cathode and the half-cell A is the anode

Part B. 0.017V

Explanation:

Part A

The electrons must go from the anode to the cathode. At the anode oxidation takes place, and at the cathode a reduction, so the flow of electrons must go from the less concentrated solution to the most one (at oxidation the concentration intends to increase, and at the reduction, the concentration intends to decrease).

So, the half-cell B is the cathode and the half-cell A is the anode.

Part B

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3 years ago
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