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Hitman42 [59]
3 years ago
15

What is the end result of a nuclear fusion reaction? two new atoms with smaller nuclei form molecule of atoms forms one new atom

with a larger nucleus forms new bonds between atoms are formed
Chemistry
2 answers:
Arlecino [84]3 years ago
7 0

Answer: Option (c) is the correct answer.

Explanation:

When two small or light atomic nuclei combine together then it results in the formation of a larger nuclei.This process is known as nuclear fusion.

For example, ^{2}_{1}H + ^{3}_{1}H \rightarrow ^{4}_{2}He + ^{1}_{0}n + Energy

Whereas when a larger atomic nuclei splits into two small atomic nuclei then it is known as a nuclear fission.

For example, ^{235}_{92}U + ^{1}_{0}n \rightarrow ^{90}_{36}Kr + ^{143}_{56}Ba + 3^{1}_{0}n

Thus, we can conclude that the end result of a nuclear fusion reaction is one new atom with a larger nucleus.

Mashutka [201]3 years ago
6 0
The end result of a nuclear fusion reaction is one new atom with a larger nucleus.Nuclear fusion is a reaction in which two or more atomic nuclei come close enough to form one or more different atomic nuclei and sub atomic particles. Fusion of light elements toward these releases energy, while fusion producing nuclei heavier than these elements will result in energy retained by the resulting nucleons, and the resulting reaction is endothermic.
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A chemist examines an ionic compound that contains magnesium and one other element. She
Igoryamba

Group 7

Explanation:

The unknown element belongs to the seventh group on the periodic table of elements.

Ionic bonds are usually formed between metals and nonmetals. They formed by the transfer of electrons from the less electronegative specie to the more electronegative one.

The metals usually lose electron because they are highly electropositive species.

  • If we have a magnesium atom with two valence electrons.
  • To form ionic bonds, it must transfer the two electrons to another atom.
  • The other atom, a nonmetal must be ready to accommodate and receive the donated electrons.
  • This ensure that its own octet is complete.
  • Group 6 elements requires 2 electrons to have a complete octet.
  • They can receive the two electrons

But we were told that there are two atoms of that element for each of the magnesium atom;

  the atom must have a capacity of collecting one electron each to be stable.

Such atoms are found in Group 7 on the periodic table.

learn more:

Ionic bond brainly.com/question/6071838

#learnwithBrainly

3 0
3 years ago
How do geologists monitor volcanoes?
Radda [10]

Answer:

<h2>Scientists use a wide variety of techniques to monitor volcanoes, including seismographic detection of the earthquakes and tremor that almost always precede eruptions, precise measurements of ground deformation that often accompanies the rise of magma, changes in volcanic gas emissions, and changes in gravity.</h2>
5 0
3 years ago
Net ionic equation for NaOH(aq) + NH4Br(aq) —&gt; NaBr(aq) + NH3(g) + H2O(l)
Greeley [361]

Answer:

OH⁻(aq) + NH₄⁺(aq) →  NH₃(g) + H₂O(l)

Explanation:

The net ionic equation is a way yo write a chemical equation that list only the species that are involved in the reaction.

For the reaction:

NaOH(aq) + NH₄Br(aq) → NaBr(aq) + NH₃(g) + H₂O(l)

Ionic equation is:

Na⁺(aq) + OH⁻(aq) + NH₄⁺(aq) + Br⁻(aq) → Na⁺(aq) + Br⁻(aq) + NH₃(g) + H₂O(l)

<em>-Ions comes from the species that are in aqueous phase-</em>

And net ionic equation is:

<em>OH⁻(aq) + NH₄⁺(aq) →  NH₃(g) + H₂O(l)</em>

<em />

<em />

8 0
3 years ago
5) Calculate the molality of 0.210 mol of KBr dissolved in 0.075kg pure<br> water?
Margaret [11]

Answer:

\boxed {\boxed {\sf 2.8 \ m }}

Explanation:

The formula for molality is:

m=\frac{moles \ of \ solute}{kg \ of \ solvent}

There are 0.210 moles of KBr and 0.075 kilograms of pure water.

moles= 0.210 \ mol \\kilograms = 0.075 \ kg

Substitute the values into the formula.

m= \frac{ 0.210 \ mol }{0.075 \ kg}

Divide.

m= 2.8 \ mol/kg= 2.8 \ m

The molality is <u>2.8 moles per kilogram</u>

5 0
3 years ago
What positions in the ring of a purine nucleotide in DNA have the potential to form hydrogen bonds but are not involed in watson
m_a_m_a [10]

Answer:

N-1

Explanation:

All nitrogen positions in purine rings (N-1, N-3, N-7 and N-9) have the potential to form hydrogen bonds. Among them, only N-1 is involved in Watson-Crick base pairing hydrogen bond with a pyridimine. N-3 and N-7 are available to form further hydrogen bonds and N-9 is involved in a N-glycosyl linkage with a desoxyribose.

6 0
3 years ago
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