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mario62 [17]
4 years ago
5

Which example best shows conservation of resources?

Chemistry
2 answers:
zaharov [31]4 years ago
6 0

Answer:

D.

Explanation:

I took this test as a freshman and this was the only question of 4 that I can remember

grin007 [14]4 years ago
4 0

。☆✼★ ━━━━━━━━━━━━━━  ☾  

Conservation means limiting waste of.

Therefore, the correct answer would be option D

Have A Nice Day ❤    

Stay Brainly! ヅ    

- Ally ✧    

。☆✼★ ━━━━━━━━━━━━━━  ☾

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The fuel used in many disposable lighters is liquid butane, C4H10. Butane has a molecular weight of 58.1 grams in one mole. How
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A gas mixture containing He, Ne, and Ar exerts a pressure of 3.00 atm. What is the partial pressure of each gas present in the m
matrenka [14]
<h3>Answer:</h3>

Partial pressure of He(P(He) = 1.5 atm.

Partial pressure of Ne(P(Ne) = 1 atm.

Partial pressure of Ar(P(Ar) = 0.5 atm.

<h3>Explanation:</h3>

According to Dalton law of partial pressure the sum of partial pressures of individual gases in a gaseous mixture is equivalent to the total pressure.

The partial pressure of a gas in a gaseous mixture is given by the product of the mole fraction and the total pressure.

Our gaseous mixture contains He, Ne, and Ar and the total pressure is 3 atm.

Since we are given the ratios of the gases in the mixture, we can calculate the partial pressure of each gas.

P(He) = 3/6 × 3 atm.

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P(Ne) = 2/6 × 3 atm.

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P(Ar) = 1/6 × 3 atm.

        = 0.5 atm

Therefore, the partial pressures of gases He, Ne and Ar are 1.5 atm, 1 atm, and 0.5 atm respectively.

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Environmental studies usually involve an analysis of precipitation and its response to pollution. To quantify the degree of cont
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The molarity of the lake water is 0.00001 M and the pH of lake water is 5.

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Data given:

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volume of the base solution Vbase = 0.1 ml or 0.0001 litre

volume of lake water Vlake = 1000ml  or 1 litre

molarity of the lake water, Mlake = ?

Using the formula for titration:

Mbase X Vbase = Mlake X

Mlake = \frac{Mbase X Vbase }{Vlake}

Putting the values in the equation:

Mlake = \frac{0.0001 X 0.1}{1}

Mlake = 0.00001 M

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pH = - log_{10} [H^{+}]

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