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3 years ago

How does an element differ from a compound? How are they similar?

Chemistry

1 answer:

ArbitrLikvidat [17]3 years ago

7 0

Explanation:

<u>DIFFERENCE:</u>

The difference between element and compound is that the element is the substance which is made of same type of the atoms, whereas the compound is made of different elements which are combined in definite proportions.

<u>SIMILARITY:</u>

Elements and Compounds both contains atoms. They both have bonds linking atoms together. They both are pure substances and homogeneous in composition.

Examples of elements include copper, hydrogen, oxygen, etc.

Examples of compounds include water, salt NaCl, etc.

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3 years ago

Read 2 more answers

How much work is done if an object moves 4.5 m in has 12 Newtons of force on it

Cloud [144]

The formula of work is Work (Joules)=Force (Newtons) · distance in the direction of the force (meters), therefore its just a matter of replacing factors.

Work done = 12 · 4.5= 54 joules

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3 years ago

Be sure to answer all parts. What is the [H3O+] and the pH of a buffer that consists of 0.26 M HNO2 and 0.89 M KNO2? (K, of HNO2

Aleksandr-060686 [28]

Answer : The $H_3O^+$ ion concentration is, $1.12\times 10^{-3}M$ and the pH of a buffer is, 2.95

Explanation : Given,

$K_a=7.1\times 10^{-4}$

Concentration of $HNO_2$ (weak acid)= 0.26 M

Concentration of $KNO_2$ (conjugate base or salt)= 0.89 M

First we have to calculate the value of $pK_a$ .

The expression used for the calculation of $pK_a$ is,

$pK_a=-\log (K_a)$

Now put the value of $K_a$ in this expression, we get:

$pK_a=-\log (7.1\times 10^{-4})$

$pK_a=4-\log (7.1)$

$pK_a=3.15$

Now we have to calculate the pH of the solution.

Using Henderson Hesselbach equation :

$pH=pK_a+\log \frac{[Salt]}{[Acid]}$

$pH=pK_a+\log \frac{[KNO_2]}{[HNO_2]}$

Now put all the given values in this expression, we get:

$pH=3.15+\log (\frac{0.89}{0.26})$

$pH=2.95$

The pH of a buffer is, 2.95

Now we have to calculate the $H_3O^+$ ion concentration.

$pH=-\log [H_3O^+]$

$2.95=-\log [H_3O^+]$

$[H_3O^+]=1.12\times 10^{-3}M$

The $H_3O^+$ ion concentration is, $1.12\times 10^{-3}M$

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3 years ago

Increased irrigation demands: decrease the rate of transpiration increase the rate of surface water evaporation change the amoun

drek231 [11]

Answer: Increase the rate of surface water evaporation

Irrigation is a process, in which the crops are supplied with water, to ensure their proper growth. Increased in the irrigation supply can be because of the environmental conditions like hot summer season or may be because of the type of soil is semi arid or arid means the soil does not retains moisture efficiently. This will result in increase in the rate of evaporation of the surface water.

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3 years ago

What is chemisorption?

Blababa [14]

When the substance being absorbed is held together by chemical bonds.

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