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aalyn [17]
3 years ago
8

How does an element differ from a compound? How are they similar?

Chemistry
1 answer:
ArbitrLikvidat [17]3 years ago
7 0

Explanation:

<u>DIFFERENCE:</u>

The difference between element and compound is that the element is the substance which is made of same type of the atoms, whereas the compound is made of different elements which are combined in definite proportions.

<u>SIMILARITY:</u>

Elements and Compounds both contains atoms. They both have bonds linking atoms together. They both are pure substances and homogeneous in composition.

Examples of elements include copper, hydrogen, oxygen, etc.

Examples of compounds include water, salt NaCl, etc.

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If 5 mol of oxygen gas effuses through an opening in 10 seconds, how long will it take for the same amount of hydrogen gas to ef
andrezito [222]

Answer:

B

Explanation:

Recall the law of effusion:

\displaystyle \frac{r_1}{r_2} = \sqrt{ \frac{\mathcal{M}_2}{\mathcal{M}_1} }

Because 5 mol of oxygen was effused in 10 seconds, the rate is 0.5 mol/s.

Let the rate of oxygen be <em>r</em>₁ and the rate of hydrogen be <em>r</em>₂.

The molecular weight of oxygen gas is 32.00 g/mol and the molecular weight of hydrogen gas is 2.02 g/mol.

Substitute and solve for <em>r</em>₂:

\displaystyle \begin{aligned} \frac{(0.5\text{ mol/s})}{r_2} & = \sqrt{\frac{(2.02\text{ g/mol})}{(32.00\text{ g/mol})}} \\ \\  r_2 & = \frac{0.5\text{ mol/s}}{\sqrt{\dfrac{(2.02\text{ g/mol})}{(32.00\text{ g/mol})}}} \\ \\ & = 2.0\text{ mol/s}\end{aligned}

Because there are 5 moles of hydrogen gas:

\displaystyle 5.0\text{ mol} \cdot \frac{1\text{ s}}{2.0\text{ mol}} = 2.5\text{ s}

In conclusion, it will take about 2.5 seconds for the hydrogen gas to effuse.

Check: Because hydrogen gas is lighter than oxygen gas, we expect that hydrogen gas will effuse quicker than oxygen gas.

6 0
2 years ago
What is 44.25 l to ml
Oliga [24]

44250

hope this helps

6 0
3 years ago
Will mark brainliest!!
olga2289 [7]

Answer:

I think its B im not sure

but i hope this helps

6 0
3 years ago
Question 3 (1 point)
irina1246 [14]

false

Explanation:

i took the test

4 0
2 years ago
Read 2 more answers
Determine the pH of a 5x10^-4 M solution of Ca(OH)2
miss Akunina [59]
Ca(OH)₂ ==> Ca²⁺ + 2 OH<span>-   

Ca(OH)</span>₂ is <span>strong Bases</span><span>

</span>Therefore,  the [OH-] equals 5 x 10⁻⁴ M. For every Ca(OH)₂ you produce 2 OH⁻<span>.
</span>
pOH = - log[ OH⁻]

pOH = - log [ <span>5 x 10⁻⁴ ]

pOH = 3.30

pH + pOH = 14

pH + 3.30 = 14

pH = 14 - 3.30

pH = 10.7

hope this helps!</span>
5 0
3 years ago
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