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tangare [24]
3 years ago
8

The voltage in a flashlight bulb is 6.0 volts and has a resistance of 24 ohms. Calculate the current

Chemistry
2 answers:
taurus [48]3 years ago
5 0

Answer:

Thanks for the points

Explanation:

Genrish500 [490]3 years ago
3 0
The answer will be .25 because R=v/I so it would be 24=0.6/I you divide it and you’ll get .25 or 0.25
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In the balanced chemical reaction for the combustion of acetylene (used in welding torches), determine at standard temperature a
Tpy6a [65]

Answer:

8L of CO2

Explanation:

The equation for the reaction is given below:

2C2H2 + 5O2 —> 4CO2 + 2H2O

From the equation above,

5L of O2 produced 4L of CO2.

Therefore, 10L of O2 will produce = (10 x 4)/5 = 8L of CO2

Therefore, 8L of CO2 is produce

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3 years ago
How can you differentiate the Atomic Structure and the Bohr Model? In other words, how is the Atomic Structure different from th
Tatiana [17]

Answer:

Bohr thought that electrons orbited the nucleus in circular paths; whereas in the modern view atomic electron structure is more like 3D standing waves. Bohr built upon Rutherford's model of the atom. ... He believed that electrons moved around the nucleus in circular orbits with quantised potential and kinetic energies.

Explanation:

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3 years ago
An unknown compound contains only carbon, hydrogen, and oxygen (CxHyOz). Combustion of 2.50g of this compound produced 3.67g of
REY [17]
The solution to the problem is as follows:

 <span>a) 

C + O2 = CO2 

Molar mass CO2 = 44 g/mol 

3.67 g CO2 * 1 mol / 44 g = 

=0.0834 mol CO2 = 0.0834 mol C 

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4 0
3 years ago
PLEASE HELP ME ASAP!!!!!!!!!
snow_lady [41]

Answer:

the answer is c 8.91g/cm³

6 0
3 years ago
A compound is found to contain 37.32 % phosphorus , 16.88 % nitrogen , and 45.79 % fluorine by
Alla [95]

Answer: 1. The empirical formula is PNF_2  

2. The molecular formula is PNF_2

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of P = 37.32 g

Mass of N = 16.88 g

Mass of F = 45.79 g

Step 1 : convert given masses into moles.

Moles of P =\frac{\text{ given mass of P}}{\text{ molar mass of P}}= \frac{37.32g}{31g/mole}=1.20moles

Moles of N =\frac{\text{ given mass of N}}{\text{ molar mass of N}}= \frac{16.88g}{14g/mole}=1.20moles

Moles of F =\frac{\text{ given mass of F}}{\text{ molar mass of F}}= \frac{45.79g}{19g/mole}=2.41moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For P = \frac{1.20}{1.20}=1

For N = \frac{1.20}{1.20}=1

For F =\frac{2.41}{1.20}=2

The ratio of P: N: F= 1: 1: 2  

Hence the empirical formula is PNF_2

The empirical weight of PNF_2= 1(31)+1(14)+2(19)= 82.98 g.

The molecular weight = 82.98 g/mole

Now we have to calculate the molecular formula.

n=\frac{\text{Molecular weight}}{\text{Equivalent weight}}=\frac{82.98}{82.98}=1

The molecular formula will be=1\times PNF_2=PNF_2

3 0
3 years ago
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