The relationship between pH and pKa of buffer solution in given atomic view:
In figure I pH= pKa ( since [HA] =[A-] )
In figure II pH > pKa ( since [A-] > [HA] )
In figure III pH < pKa ( since [A-] < [HA] )
The pH and pKa are related by the Henderson-Hasselbalch equation. It should not be used for concentrated solutions, extremely low pH acids, or extremely high pH bases because it is simply an approximation.
pH = pKa + log(conjugate base/weak acid).
pH equals pKa plus log ([A-] / [HA]).
pH is determined by dividing the weak acid concentration by the log of the conjugate base concentration and the pKa value.
About halfway to the equivalence point:
pH = pKa
It's important to note that this equation is familiar with the connection because it is sometimes written for the Ka value rather than the pKa value.
pKa = – log Ka
Hence, value of pH depend on relative concentration of [A-] and HA]
To know more about Ka.
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WAS THIS HELPFUL......
Answer: they will meet and make a biger wave then seperat
Explanation: When two or more waves meet, they interact with each other. The interaction of waves with other waves is called wave interference. Wave interference may occur when two waves that are traveling in opposite directions meet. The two waves pass through each other, and this affects their amplitude.
Answer:
E. Q < K and reaction shifts right
Explanation:
Step 1: Write the balanced equation
A(s) + 3 B(l) ⇄ 2(aq) + D(aq)
Step 2: Calculate the reaction quotient (Q)
The reaction quotient, as the equilibrium constant (K), only includes aqueous and gaseous species.
Q = [C]² × [D]
Q = 0.64² × 0.38
Q = 0.15
Step 3: Compare Q with K and determine in which direction will shift the reaction
Since Q < K, the reaction will shift to the right to attain the equilibrium.
