Answer:
C
Explanation:
The chemical energy stored in the match changed to thermal energy and light energy.
The case is acidic since calculated pH is below 7 that is 2.3
The hydroxide and hydrogen ion levels in a solution are the sources for calculating pOH and pH levels, respectively, and are the basis of whether a solution is acidic or basic
[H₃O+]=5.3×10⁻³M
To determine the hydroxide ion concentration, we use:
[OH−][H3O+]=1×10⁻¹⁴
We isolate the hydroxide ion concentration:
[OH−]=1×10−145.3×10⁻³M
Solving this, we obtain:
[OH−]=1.9×10−¹²M
We can determine whether the solution is acidic or basic by calculating the pH level:
pH=−log[H3O+]
We substitute in the hydronium ion concentration given:
pH=−Log(5.3×10−3)pH=2.3
Since the pH is below 7, the solution is acidic
Learn more about hydroxide ion here-
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Answer: D
Explanation:
A reducing agent is a species that reduces other compounds, and is thereby oxidized. The whole compound becomes the reducing agent. In other words, of a compound is oxidized, then they are the reducing agent. On the other hand, if the compound is reduced, it is an ozidizing agent.
Since we have established that a reducing agent is the compound being oxidized, we know that A is not our answer. An oxidized compound is losing electrons. Choice A states exactly this.
For B, this is true as we have established this already.
C is also correct. Since a reducing agent loses electrons, it becomes more positive. This makes the oxidation number increase.
D would be our correct answer. It is actually a good oxidizing agent is a metal in a high oxidation state, such as Mn⁷⁺.
Answer:
<h2>The answer is 4 m/s²</h2>
Explanation:
The acceleration of an object given it's mass and the force acting on it can be found by using the formula
where
a is the acceleration
f is the force
m is the mass
From the question
f = 20 N
m = 5 kg
We have
We have the final answer as
<h3>4 m/s²</h3>
Hope this helps you
Answer:
1 Joule=0.2390057361 Calorie
789kj=789×0.2390057361×1000
=188575.5257829calorie
Explanation:
Hope u have understand
