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Nesterboy [21]
3 years ago
8

(20 Pt.s) Guys! You have to explain:

Chemistry
1 answer:
Nadya [2.5K]3 years ago
3 0

Weakly basic drugs behaves different from acidic drugs which is discussed below.

<h3><u>Explanation</u>:</h3>

Weakly basic drugs are those drugs which have an amine group associated with them. They are able to gain a proton to be come positively charged.

So drugs like quinine, ephedrine and aminopyrine which are basic got completely ionised in stomach.

The stomach can absorb those compounds which are lipid soluble. The acidic drugs like alcohols, Salicylic acid, aspirin, thiopental, secobarbital and antipyrine etc which are acidic gets absorbed by means of <em>diffusion</em> through the membrane.

But the basic drugs have charges on them which makes them lipophobic. So they cannot get absorbed through stomach. However weakly basic drugs sometimes get absorbed depending on their ionisation extent.

The rest goes to small intestine which has basic environment and there they gets absorbed via diffusion or facilitated diffusion.

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As with any combustion reaction, the products of combusting a hydrocarbon fuel (CxHy) with oxygen (O2) are carbon dioxide (CO2)
melisa1 [442]

<u>Answer:</u>

<em>5 molecules of oxygen will be present </em>

<u>Explanation:</u>

<em>In this reaction combustion is taking place hence there must be presence of oxygen in it. </em>

We don't know the initial amount of carbon molecules in hydrogen molecules present hence the equation goes:-

CxHy + O_2 => CO_2+ H_2O

Mass of  fuel 16.74 grams, Mass of carbon dioxide is 1198 gram and water is 0.0654 remaining mass of  fuel is 16.70 g.  Hence amount of fuel used up is 0.04 gram  

<em>0.04 + O => 0.1198 + 0.0654</em>

<em>Weight of products is 0.1852 and weight of oxygen is 0.1452 </em>

<em>No of molecules will be \frac {(0.1452 \times 6.023 \times 10^-^2^3)}{ (1.661 \times 10^-^2^4)} = 5molecules </em>

3 0
4 years ago
Exercise while in space is important because it PREVENTS what?
dsp73

Answer:

bone loss and muscle deterioration

Explanation:

this helps the body keep thriving and bones strong and muscles in tact

8 0
4 years ago
What is the wavelength of radiation that has a frequency of 7.2×10^11 s−1 ?
Airida [17]

Explanation:

It is known that relation between wavelength and frequency is as follows.

                  \lambda = \frac{c}{\nu}

where,        \lambda = wavelength

                       c = speed of light = 3 \times 10^{8} m/s

                  [/tex]\nu[/tex] = frequency

It is given that frequency is 7.2 \times 10^{11} s^{-1}. Hence, putting this value into the above formula and calculate the wavelength as follows.

                    \lambda = \frac{c}{\nu}

                    \lambda = \frac{3 \times 10^{8} m/s}{7.2 \times 10^{11} s^{-1}}

                             = 0.416 \times 10^{-3} m

or,                         = 4.16 \times 10^{-4} m

Thus, we can conclude that wavelength of given radiation is 4.16 \times 10^{-4} m.

6 0
3 years ago
Luca wants to identify and quantity the chemicals causing air pollution in a city, but he is using a manual air sampler to colle
xenn [34]

Answer

Manual samplers are prone to effects of temperature, speed of wind and air concentrations.

Explanation

Manual samplers face several challenges that can act as drawbacks to obtaining accurate results. They are subjected to effects of sampling duration where long sampling times are needed to obtain adequate mass for detection. Manual samplers face challenges when measuring non-volatile species because particles are observed into the adsorption medium at a slower rate of diffusion.

5 0
4 years ago
In the chemical reaction NaHCO3 + CH3COOH → CH3COONa + H2O +CO2, 83 g of sodium bicarbonate reacts with 70 g of acetic acid. Whi
krok68 [10]
MNaHCO₃: 23+1+12+(48×3) = 84g
mCH₃COOH: 12+(1×3)+12+(16×2)+1 = 60g
.................
84g NaHCO₃ react with 60g CH₃COOH
83g NaHCO₃ react with...........

84g ----- 60g
83g ----- X
X = 59,29g CH₃COOH

We used 70g CH₃COOH, it' too much.
So, acetic acid is excess reagent, and sodium bicarbonate is limiting reagent.
_______________________________
B) Amount of CH3COOH is in excess.

:•)
3 0
4 years ago
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