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Dmitry [639]
2 years ago
9

The particle is an electron. the field slows down the electron without deflecting it. what is the direction of the electric fiel

d? choose the best answer.
Physics
1 answer:
sammy [17]2 years ago
7 0

The particle is an electron. The field slows down the electron without deflecting it. The direction of the electric field is <u>right.</u>

In physics, the motion of electrically charged particles gives rise to a field called an electric field. It is measured in force per unit charge.

This field applies force on other charged particles.

Particles bearing opposite charges attract each other while particles having similar charges repel each other in the field.

If a positive charge is placed in the field then the field line moves in an outward direction and for a negative charge, the direction of the lines is inward.

If you need to learn more about electric field click here:

brainly.com/question/26199225

#SPJ4

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13.77 Billion years old

Explanation:

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What are the adaptions of the tundra
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Julian tests four springs and records the results in the table
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Answer:

list of spring in order of increasing spring constant is given by,

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Spring W:

Magnitude of Force applied on the spring is given by,

F = k x

Where, F = force applied

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k = 20 / 0.5

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Spring X:

Magnitude of Force applied on the spring is given by,

F = k x

Where, F = force applied

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Spring Y:

Magnitude of Force applied on the spring is given by,

F = k x

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Spring Z:

Magnitude of Force applied on the spring is given by,

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Where, F = force applied

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8 0
3 years ago
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A basketball player makes a bounce pass by throwing the ball with a speed of 5.3 m/s and at an angle 12° below the horizontal. I
Dima020 [189]

Answer:

ball hit the ground from her feet is 1.83 m far away

Explanation:

given data

speed = 5.3 m/s

angle = 12°

height = 1 m

to find out

how far from her feet ball hit ground

solution

we consider here x is horizontal component and y is vertical component

so in vertical

velocity will be = v sin12

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in horizontal , velocity we know v = 5.3 m/s

so from motion of equation

s = ut + 0.5×a×t²

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1 = 1.1 ( t) + 0.5×9.8×t²

solve it we get t

t = 0.353 s

and

horizontal distance is = vcos12 × t

so horizontal distance = 5.3×cos12 × ( 0.353)

horizontal distance = 1.83 m

so ball hit the ground from her feet is 1.83 m far away

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I hope this helps!
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