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2 years ago

A backyard swimming pool holds 150 cubic yards (yd3) of water. what is the weight of the water in pounds?

Physics

1 answer:

Crank2 years ago

5 0

solution:

$1yd^3=(0.9144m)^3\\
therefore,\\
150yd^3=150yd^3\times\frac{(0.9144m)^3}{1yd^3}\\
=114.68m^3
convert m^3 to cm^3by the conversion factor as follow\\
1m^3=(100)cm^3\\
114.68m^3=114.68\times\frac{(100cm)3}{1m^3}\\
convert cm^3 to mL by the conversion factor as follow\\
1cm^3=1mL\\
114.68\times10^6cm^3=114.68\times10^6cm^3\times\frac{1mL}{1cm^3}\\
=114.68\times10^6mL\\
convert mL to g by the conversion factor as follow\\
1mL=1g\\therefore,\\
114.68\times10^6mL=114.68\times10^6mL\times\frac{1g}{1mL}\\
114.68\times10^6g\\
convert g to kg the conversion factor as follow\\
1g=10^-3kg\\
therefore,\\
114.68\times10^6=114.68\times10^6g\times\frac{10^-3kg}{1g}\\
=114.68\times10^3kg\\
convert kg to Ib by the conversion factor as follow\\
1kg=2.2Ib\\
therefore,\\
114.68\times10^3kg=114.68\times10^3kg\times\frac{2.2Ib}{1kg}\\
=2.52\times10^5Ib$

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