Question

A backyard swimming pool holds 150 cubic yards (yd3) of water. what is the weight of the water in pounds?

Answer 1

solution:

$1yd^3=(0.9144m)^3\\ therefore,\\ 150yd^3=150yd^3\times\frac{(0.9144m)^3}{1yd^3}\\ =114.68m^3 convert m^3 to cm^3by the conversion factor as follow\\ 1m^3=(100)cm^3\\ 114.68m^3=114.68\times\frac{(100cm)3}{1m^3}\\ convert cm^3 to mL by the conversion factor as follow\\ 1cm^3=1mL\\ 114.68\times10^6cm^3=114.68\times10^6cm^3\times\frac{1mL}{1cm^3}\\ =114.68\times10^6mL\\ convert mL to g by the conversion factor as follow\\ 1mL=1g\\therefore,\\ 114.68\times10^6mL=114.68\times10^6mL\times\frac{1g}{1mL}\\ 114.68\times10^6g\\ convert g to kg the conversion factor as follow\\ 1g=10^-3kg\\ therefore,\\ 114.68\times10^6=114.68\times10^6g\times\frac{10^-3kg}{1g}\\ =114.68\times10^3kg\\ convert kg to Ib by the conversion factor as follow\\ 1kg=2.2Ib\\ therefore,\\ 114.68\times10^3kg=114.68\times10^3kg\times\frac{2.2Ib}{1kg}\\ =2.52\times10^5Ib$