7) (x, TU, TB) = (4, 8, 13)
9) (x, RS, MN) = (8, 41, 41)
11) (AB, BC, AC) = (42, 42, 84)
<h3>What are the values of the variable x and the lengths of the line segments?</h3>
In this question we have three cases of colinear line segments, each of them can be solved by using definitions from Euclidean geometry and algebraic handling:
Case 7 - TU = 2 · x, UB = 3 · x + 1, TB = 21
TB = TU + UB
21 = 2 · x + 3 · x + 1
21 = 5 · x + 1
5 · x = 20
x = 4
Then, the lengths of each line segment are:
TB = 21
TU = 2 · 4
TU = 8
UB = 3 · 4 + 1
UB = 13
The solutions are (x, TU, TB) = (4, 8, 13).
Case 9 - RS = 3 · x + 17, MN = 7 · x - 15
RS = MN
3 · x + 17 = 7 · x - 15
4 · x = 32
x = 8
And the lengths of each line segment are:
RS = MN = 41
The solutions are (x, RS, MN) = (8, 41, 41).
Case 11 - AB = 2 · x - 8, BC = x + 17
AB + BC = AC
AB = BC
2 · x - 8 = x + 17
x = 25
And the lengths of each line segment are:
AB = 2 · 25 - 8
AB = 42
BC = AB
BC = 42
AC = 42 + 42
AC = 84
The solutions are (AB, BC, AC) = (42, 42, 84).
To learn more on line segments: brainly.com/question/25727583
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