Answer:
Total distance = 22.5 kilometers
Explanation:
Let the first distance be A.
Let the second distance be B
Given the following data;
Speed A = 30km/h
Time A = 15 minutes to hours = 15/60 = 0.25 hour
Speed B = 60km/h
Time B = 15 minutes to hours = 15/60 = 0.25 hour
Now, to find the respective distance traveled;
Distance A = speed A * time A
Distance A = 30 * 0.25
Distance A = 7.5 km
Distance B = speed B * time B
Distance B = 60 * 0.25
Distance B = 15 km
Next, we calculate the total distance traveled;
Total distance = Distance A + distance B
Total distance = 7.5 + 15
Total distance = 22.5 kilometers.
Therefore, the total distance covered by the object is 22.5 kilometers.
<u>First Symbol </u>: Cobalt (Co)
Its Group Number - 9
Its Period Number - 4
Its Family Name - Transition Metal
<u>Second Symbol</u> : Silicon (Si)
Its Group Number - 14
Its Period Number - 2
Its Family Name - Semiconductor
<u>Third Symbol</u> : Astatine (At)
Its Group Number - 17
Its Period Number - 6
Its Family Name - Halogen
<u>Fourth Symbol </u>: Magnesium (Mg)
Its Group Number - 2
Its Period Number - 3
Its Family Name - Alkaline Earth Metal
<u>Fifth Symbol</u> : Xenon (Xe)
Its Group Number - 18
Its Period Number - 5
Its Family Name - Noble Gas
Answer:
As the wind travels across the earth, air masses and global winds do not travel in straight lines. in the Northern hemisphere air veers to the right and in southern hemisphere to the left. this motion can result in large circulating weather systems, as air blows away from or into a high or low pressure areas.
on earth the main differences in air pressure are caused by differences in temperatures. cool air produces high air pressure and warm air produces low air pressure.
Answer:
(A) The maximum height of the ball is 40.57 m
(B) Time spent by the ball on air is 5.76 s
(C) at 33.23 m the speed will be 12 m/s
Explanation:
Given;
initial velocity of the ball, u = 28.2 m/s
(A) The maximum height
At maximum height, the final velocity, v = 0
v² = u² -2gh
u² = 2gh

(B) Time spent by the ball on air
Time of flight = Time to reach maximum height + time to hit ground.
Time to reach maximum height = time to hit ground.
Time to reach maximum height is given by;
v = u - gt
u = gt

Time of flight, T = 2t

(C) the position of the ball at 12 m/s
As the ball moves upwards, the speed drops, then the height of the ball when the speed drops to 12m/s will be calculated by applying the equation below.
v² = u² - 2gh
12² = 28.2² - 2(9.8)h
12² - 28.2² = - 2(9.8)h
-651.24 = -19.6h
h = 651.24 / 19.6
h = 33.23 m
Thus, at 33.23 m the speed will be 12 m/s
Answer:
b) the length of car
Explanation:
This is because 520 divided by 343 m/s.) would equal the length of a car.