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rosijanka [135]
2 years ago
11

A solution has an H3O+ concentration of 3.5 x 10^-5 M. Is it acidic or basic?

Chemistry
1 answer:
irakobra [83]2 years ago
7 0

The mass of NaCl produced is 0.117 g.

<h3>What is the pH?</h3>

The pH of a solution is what tells us if the solution is acidic or basic. The solution is acidic if the pH of the solution is less than 7.

1) pH = - log(3.5 x 10^-5 M)

= 4.45

Thus the solution is acidic.

2) We can see that the concentration as given is the concentration of OH^-

[OH ] = 4.0 x 10^-3 M

pOH = -log (4.0 x 10^-3 M)

pOH = 2.39

pH = 14 -  2.39

pH = 11.61

The equation of the reaction is; NaOH + HCl ----- > NaCl + H2O

Number of moles of NaOH =  0.40 M * 10/1000 = 0.004 moles

Number of moles of HCl = 0.20 M  * 10/1000 = 0.002 moles

We can see that HCl is the limiting reactant

Mass of NaCl produced ;

0.002 moles * 58.5 g/mol = 0.117 g

Learn more about reaction:brainly.com/question/3588292

#SPJ1

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Answer:

Number of moles = mass/molar mass

Explanation:

Given data:

mass of Al = 11 g

Moles = ?

Solution:

Formula:

Number of moles = mass/molar mass

Molar mass of aluminium is 27 g/mol

Now we will put the values in formula.

Number of moles = 11 g/ 27 g/mol

Number of moles = 0.41

The number of moles in 11 g Al are 0.41 mol.

5 0
3 years ago
Copper has two naturally occurring isotopes, 63Cu (isotopic mass 62.9296 amu) and 65Cu (isotopic mass 64.9278 amu). If copper ha
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Answer:

Percentage of first isotope = 69.152 %

Percentage of second isotope =  30.848 %

Explanation:

The formula for the calculation of the average atomic mass is:

Average\ atomic\ mass=(\frac {\%\ of\ the\ first\ isotope}{100}\times {Mass\ of\ the\ first\ isotope})+(\frac {\%\ of\ the\ second\ isotope}{100}\times {Mass\ of\ the\ second\ isotope})

Given that:

For first isotope:

Let % = x %

Mass = 62.9296 amu

For second isotope:

% = 100 - x  %  (Since, there are only two isotopes)

Mass = 64.9278 amu

Average mass = 63.546 amu

Thus,  

63.546=\frac {x}{100}\times {62.9296}+\frac {(100-x)}{100}\times {64.9278}

Solving,

1.9982 x = 138.18

Thus,

<u>Percentage of first isotope = x = 69.152 %</u>

<u>Percentage of second isotope = 100 - x % = 30.848 %</u>

5 0
4 years ago
Calculate the molality of an ethylene glycol (C2H6O2) soltuion, that has a molarity of 2.07 M. The density of the solution is 1.
vlada-n [284]

Answer:

2.03

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With that information we can <u>calculate the molality</u>:

  • molality = moles of solute / kg of solvent
  • molality = 2.07 moles / (1020 ÷ 1000) = 2.03 m

Keep in mind that this is only an estimate, as we used the kg of the solution and not of the solvent.

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