Answer:
The ionization equation is
⇄
(1)
Explanation:
The ionization equation is
⇄ (1)
As the Bronsted definition sais, an acid is a substance with the ability to give protons thus, H2PO4 is the acid and HPO42- is the conjugate base.
The Ka expression is the ratio between the concentration of products and reactants of the equilibrium reaction so,
![Ka = \frac{[HPO_{4}^{-2}] [H_{3}O^{+}]}{[H_{2}PO_{4}^{-}] [H_{2}O]} = 6.2x10^{-8}](https://tex.z-dn.net/?f=Ka%20%3D%20%5Cfrac%7B%5BHPO_%7B4%7D%5E%7B-2%7D%5D%20%5BH_%7B3%7DO%5E%7B%2B%7D%5D%7D%7B%5BH_%7B2%7DPO_%7B4%7D%5E%7B-%7D%5D%20%5BH_%7B2%7DO%5D%7D%20%3D%206.2x10%5E%7B-8%7D)
The pKa is
The pKa of H2CO3 is 6,35, thus this a stronger acid than H2PO4. The higher the pKa of an acid greater the capacity to donate protons.
In the body H2CO3 is a more optimal buffer for regulating pH due to the combination of the two acid-base equilibriums and the two pKa.
If the urine is acidified, according to Le Chatlier's Principle the equilibrium (1) moves to the left neutralizing the excess proton concentration.
Answer:
When the transfer of electrons occurs, an electrostatic attraction between the two ions of opposite charge takes place and an ionic bond is formed. A salt such as sodium chloride (NaCl) is a good example of a molecule with ionic bonding
I Think that the answer is 15.2096 Kilograms, but I might be wrong.
The dilution factor of the unknown sample is 10. The dilution factor of a solution refers to the ratio of the final volume of the now diluted solution to the initial volume of the of the initial concentrated solution.
Mathematically;
The dilution factor is given by the formula;
Dilution factor = Final volume of the now diluted solution/ Initial volume of more concentrated solution
Final volume of the now diluted solution = 100.0 ml
Initial volume of more concentrated solution = 10.00 ml
Dilution factor = 100.0 ml/10.00 ml
Dilution factor = 10
Learn more: brainly.com/question/20113402
Answer:
B. It tells whether products or reactants are favored at equilibrium.
