S^2=3^2+4^2
S^2=9+16
S^2=25
S=√25
S=5m
Answer:
Explanation:
slit separation d = .17 x 10⁻³ m.
Screen distance D = 5.35 m
angular separation of fringe = λ /d ; λ is wavelength.
Given angular separation in radian
180° = π radian
.19° =
=.0033 radian
.0033 =
λ = .0033 x d
= .0033 x .17 x 10⁻³
= 561 x 10⁻⁹
= 561 nm.
106.68 centimetres are in 3.50 feet
Answer:
a) The x coordinate of the third mass is -1.562 meters.
b) The y coordinate of the third mass is -0.944 meters.
Explanation:
The center of mass of a system of particles (), measured in meters, is defined by this weighted average:
(1)
Where:
- Mass of the i-th particle, measured in kilograms.
- Location of the i-th particle with respect to origin, measured in meters.
If we know that , , , , and , then the coordinates of the third particle are:
a) The x coordinate of the third mass is -1.562 meters.
b) The y coordinate of the third mass is -0.944 meters.
Answer:
h1/h2 =
Explanation:
Using two rolls of tissue paper : One roll dropped normally while the other drops as some holds onto a sheet of the toilet paper ( I.e. the tissue paper drops rotating about its axis )
<u>Determine the ratio of heights h1/h2</u>
mass of tissues = same
radius of tissues = same
h1 = height of tissue 1
h2 = height of tissue 2
<em>For the first tissue ( Tissue that dropped manually ) </em>
potential energy = kinetic energy
mgh = 1/2 mv^2
therefore the final velocity ( v^2 ) = 2gH ----- ( 1 )
<em>second tissue ( Tissue that dropped while rotating ) </em>
gh = ( 3 + ) ------ ( 2 )
To determine the ratio of heights we will equate equations 1 and 2
hence :
gh = ( 3 + )
∴ h1/h2 =