Answer:
Basically, it is because through probing the extreme environments of faraway massive galaxies, we can learn not only about their evolution and the history of the universe, but most importantly about the fundamental processes regulating the formation of stars.
Explanation:
Refer to the figure shown below.
W = 217/2 = 108.5 N, the weight of one half of the board.
N = W = 108.5 N, the normal reaction at B or C.
R = frictional force at B or C preventing the board from sliding.
The vertical dashed line through A is a line of symmetry.
By definition,
R = μN = 108.5μ N
where
μ = the static coefficient of friction between the board and the ground.
From geometry,
h = 2a tan(30°) = 1.1547a
Take moments about A for the member AB.
2aN - Rh -Wa = 0
2a(108.5) - 108.5μ(1.1547a) - 108.5 a = 0
217 - 125.285μ - 108.5 = 0
125.285μ = 108.5
μ = 0.866
This is the minimum required static coefficient of friction
Answer: 0.866
Answer:
A 1.56 see below
Explanation:
I will assume the 45 degree force is upward
vertical component = 600 sin 45 = 424.26 N
added to the other vertical force will total 824.26 N
F = ma
824.26 = 100 * a shows a = 8.24 m/s upward
Now we have to assume the mass is ALSO acted on by gravity and this value is given as 9.8 ( so downward is positive)
9.81 - 8.24 = 1.56 m/s^2
Answer:
Solid sphere will reach first
Explanation:
When an object is released from the top of inclined plane
Then in that case we can use energy conservation to find the final speed at the bottom of the inclined plane
initial gravitational potential energy = final total kinetic energy
now we have
here k = radius of gyration of object
also for pure rolling we have
so now we will have
so we will say that more the value of radius of gyration then less velocity of the object at the bottom
So it has less acceleration while moving on inclined plane for object which has more value of k
So it will take more time for the object to reach the bottom which will have more radius of gyration
Now we know that for hoop
k = R
For spherical shell
For solid sphere
So maximum value of radius of gyration is for hoop and minimum value is for solid sphere
so solid sphere will reach the bottom at first