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Vladimir79 [104]
3 years ago
15

Newton's third law is sometimes summarized as "for every action, there's an equal opposite reaction" but when you jump from eart

h, the earth doesn't jump backwards from you. How does Newton's third law of motion apply?
Physics
1 answer:
STatiana [176]3 years ago
3 0

When you want to jump UP, you push DOWN on the Earth. Then, because of Newton's 3rd law, the Earth immediately pushes UP on you, and this equal, opposite REaction is the force that lifts you up.

==========

By the way . . . . . The question is wrong, wrong, wrong.

When you jump up from Earth, the Earth DOES jump backwards away from you.

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HELP ASAP LIKE SERIOUSLY PLEASE. Joseph created a clay model of mountains. He formed the rock layers into a zigzag shape to crea
seraphim [82]

Answer:

The correct option is;

D. Folding of Rock

Explanation:

A fold in structural geology, is wave like form of stratified rock arrangement due to the bending of rocks which where originally deposited as flat rocks but became warped in the course of deformation of the rock layers.

The degree of bending can be very gentle such that the zig zag orientation of the rock is hardly noticeable. The bending can also very evident and in some cases the two layers may be bent up to 180, making the individually different strata once again parallel to each other.

3 0
3 years ago
Which tuning fork test evaluates conductive and sensorineural hearing loss in both ears at the same time
Flura [38]

The Rinne and Weber tests are frequently used to detect conductive and sensorineural deafness.

Another test to assess conductive and sensorineural hearing impairments is the Weber test. When sound waves cannot flow from the middle ear to the inner ear, conductive hearing loss results.

This may be brought on by issues with the eardrum, middle ear, or ear canal, such as an infection. A helpful, quick, and easy screening test for determining hearing loss is the Weber test.

The test can identify unilateral sensorineural and conductive hearing loss. Conduction hearing is mediated by the middle and outer ear. A tuning fork is used in the Weber test, a hearing screening procedure. It can identify unilateral sensorineural hearing loss and unilateral conductive hearing loss in the middle ear.

Learn more about the Weber test here brainly.com/question/9064448

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7 0
2 years ago
1. A jet lands on an aircraft carrier at a speed of 140 mi/h [ 1.00 mile = 1.61 km]
Iteru [2.4K]
Answer:

Acceleration, a = -31.29 m/s²

Explanation:

It is given that, Initial speed of the aircraft, u = 140 mi/h =

62.58 m/s

Finally, it stops, v = 0

Time taken, t = 2 s

Let a is the acceleration of the aircraft. We know that the rate of change of velocity is called acceleration of the object. It is given by :

a = t

0-62.58 2 a =

a = -31.29 m/s²

So, the acceleration of the aircraft is 31.29 m/s²

and the car is decelerating. Hence, this is the required solution.
(i found this answer becuase i could do the math)

5 0
3 years ago
A uniform cylinder of radius 10 cm and mass 20 kg is mounted so as to rotate freely about a horizontal axis that is parallel to
fomenos

Answer:

a. 0.15 kg m2

b. 19.8 rad/s

Explanation:

Metric unit conversion:

10 cm = 0.1 m

5 cm = 0.05 m

a. Using parallel axis theorem, the rotational inertia of the cylinder about the axis of rotation is the inertia about the longitudinal axis plus the product of mass and distance from the longitudinal axis to the rotational axis squared

I = I_L + md^2

whereas the inertia about the longitudinal axis of the solid cylinder is

I_L = mr^2/2 = 20*0.1^2/2 = 0.1 kgm^2

md^2 = 20*0.05^2 = 0.05 kgm^2

I = I_L + md^2 = 0.1 + 0.05 = 0.15 kg m^2

b. Assume the cylinder does not rotate about its own longitudinal axis, we can treat this as a point mass pendulum. So when it's being released from 0.05m high (release point) to 0m (lowest position), its potential energy is converted to kinetic energy:

E_p = E_k

mgh = mv^2/2

where h = 0.05 is the vertical distance traveled, v is the cylinder linear velocity at  the lowest position.g = 9.81m/s2 is the gravitational acceleration.

We can divide both sides by m

gh = v^2/2

v^2 = 2gh = 2*9.81*0.05 = 0.981

v = \sqrt{0.981} = 0.99 m/s

The angular speed is linear speed divided by the radius of rotation, which is distance from the cylinder center to the center of rotation d = 0.05 m

\omega = \frac{v}{d} = \frac{0.99}{0.05} = 19.8 rad/s

5 0
3 years ago
Select the correct answer.
S_A_V [24]
The answer is figure A
7 0
3 years ago
Read 2 more answers
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