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mihalych1998 [28]
3 years ago
8

A metaphysical poet is a writer whose

Physics
1 answer:
EastWind [94]3 years ago
8 0
Not really sure but...

<span>A metaphysical poet is a writer whose </span>focus is on universal human experiences. 
hope this helps!...
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In your own words, explain Newton’s first law of motion.
Over [174]
Newton's first law of motion states that. an object on the rest or motion is stay the same unless external force applied on it.
5 0
2 years ago
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An experimenter finds that standing waves on a string fixed at both ends occur at 24 Hz and 32 Hz , but at no frequencies in bet
Vera_Pavlovna [14]

Answer:

8 Hz

Explanation:

Given that

Standing wave at one end is 24 Hz

Standing wave at the other end is 32 Hz.

Then the frequency of the standing wave mode of a string having a length, l, is usually given as

f(m) = m(v/2L), where in this case, m could be 1. 2. 3. 4 etc

Also, another formula is given as

f(m) = m.f(1), where f(1) is the fundamental frequency..

Thus, we could say that

f(m+1) - f(m) = (m + 1).f(1) - m.f(1) = f(1)

And as such,

f(1) = 32 - 24

f(1) = 8 Hz

Then, the fundamental frequency needed is 8 Hz

4 0
3 years ago
A ball has a mass of 2g and a velocity of 3m/s. What is the ball's Kinetic Energy?​
NeTakaya

Answer: im not sire

Explanation: very sorry im not sure

7 0
3 years ago
A small logo is embedded in a thick block of crown glass (n = 1.52), 4.70 cm beneath the top surface of the glass. The block is
harkovskaia [24]

The concept required to solve this problem is the optical relationship that exists between the apparent depth and actual or actual depth. This is mathematically expressed under the equations.

d'w = d_w (\frac{n_{air}}{n_w})+d_g (\frac{n_{air}}{n_g})

Where,

d_g = Depth of glass

n_w = Refraction index of water

n_g = Refraction index of glass

n_{air} = Refraction index of air

d_w = Depth of water

I enclose a diagram for a better understanding of the problem, in this way we can determine that the apparent depth in the water of the logo would be subject to

d'w = d_w (\frac{n_{air}}{n_w})+d_g (\frac{n_{air}}{n_g})

d'w = (1.7cm) (\frac{1}{1.33})+(4.2cm)(\frac{1}{1.52})

d'w = 4.041cm

Therefore the distance below the upper surface of the water that appears to be the logo is 4.041cm

3 0
3 years ago
Which of the following forces acting upon an atom are the strongest?
iren [92.7K]

Answer:

Nuclear Forces

Explanation:

Because strong nuclear forces work best within shorter distance.

3 0
3 years ago
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