Answer:
0.4cm
Explanation:
First, you calculate the dis acceleration of the electron generated by the potential difference between the plates:
(1)
q: charge of the electron = 1.6*10^-19 C
V: potential difference between plates = 100V
m: mass of the electron
d: distance between parallel plates = 1cm = 0.01m
by replacing the values of the parameters you obtain:
you use this value in the following kinematic equation:
(2)
v: final velocity = 0m/s (until the electron stops)
from the equation (2) you calculate x, the distance traveled by the electron. But before you calculate the initial velocity of the electron by using the following equation:
Next, you replace vo in (2) to obtain x:
Then, the electron travels 0.1cm from the middle of the region between the parallel plates, hence, the distance between the electron and the negatve plate is:
0.5cm-0.1cm=0.4cm
Here’s the solution. There was no angle given so I feel this is the possible answer
Answer:
Answer for the question :
"Consider a rectangular wing mounted in a low-speed subsonic wind tunnel. The wing model completely spans the test-section, so that the flow "sees" essentially an infinite wing. The wing has a NACA 23012 airfoil section and a chord of 0.23 m, where the lift on the entire wing is measured as 200 N by the wind tunnel force balance. Determine the angle of attack if the wing span, airflow pressure, temperature, and velocity are 2 m, 1 atm, 303 K, and 42 m/s, respectively. Refer to the Appendix graphs given below for standard values" is in the attachment.
Explanation: