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Snowcat [4.5K]
3 years ago
8

When an erythrocyte is removed from circulation the iron ion of hemoglobin?

Chemistry
1 answer:
omeli [17]3 years ago
7 0
Transporting metals, ions, water-insoluble molecules, and hormones. .... When erythrocytes are removed from circulation,
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A particular voltaic cell operates with the reaction: Zn(s)+Cl2(g)--->Zn^2+(aq)+2Cl^-(aq) giving a cell potential of .853 V.
nadya68 [22]

Answer:

The amount of energy liberated will be 49.38 J.

Explanation:

The amount of energy liberated (gibbs free energy) can be calculated using the following equation:

ΔG° = -nFε

n: amount of moles of electrons transfered

F: Faraday's constant

ε: cell potential

20.0 g of Zn is equal to 0.30 mol.

Two electrons are transfered during the reaction.

Therefore, n = 2x0.30 ∴ n = 0.60

ΔG° = - 0.60 x 96.485 x 0.853

ΔG° = 49.38 J

3 0
3 years ago
Describe the difference between a ball-and-stick model and a space-filling model of a compound.
Lisa [10]
A space-filling model shows the relative amount of space each atom takes up. In other words, a space-filling model can show relative sizes of atoms. However, unlike ball-and-stick or structural models, space-filling models do not show bond lengths clearly. Bonds are not really like sticks in a ball-and-stick model.
4 0
3 years ago
Which is transferred due to a temperature difference?
Sliva [168]

Answer:

A

Explanation:

heat energy is transfered through a hot object touching a cold object

5 0
3 years ago
Which equation is used to calculate the specific heat of the metal?
algol [13]

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3 0
3 years ago
A mixture of ethyl acetate vapour and air has a relative saturation of 50% at 303 K and a total pressure of 100 kPa. If the vapo
AURORKA [14]

Answer : The correct option is, (b) 0.087

Explanation :

The formula used for relative saturation is:

\text{Relative saturation}=\frac{P_A}{P_A^o}

where,

P_A = partial pressure of ethyl acetate

P_A^o = vapor pressure of ethyl acetate

Given:

Relative saturation = 50 % = 0.5

Vapor pressure of ethyl acetate = 16 kPa

Now put all the given values in the above formula, we get:

0.5=\frac{P_A}{16kPa}

P_A=8kPa

Now we have to calculate the molar saturation.

The formula used for molar saturation is:

\text{Molar saturation}=\frac{P_{vapor}}{P_{\text{vapor free}}}

and,

P(vapor free) = Total pressure - Vapor pressure

P(vapor) = P_A = 8 kPa

So,

P(vapor free) = 100 kPa - 8 kPa = 92 kPa

The molar saturation will be:

\text{Molar saturation}=\frac{P_{vapor}}{P_{\text{vapor free}}}

\text{Molar saturation}=\frac{8kPa}{92kPa}=0.087

Therefore, the molar saturation is 0.087

5 0
3 years ago
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