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3 years ago

When an erythrocyte is removed from circulation the iron ion of hemoglobin?

1 answer:

7 0

Transporting metals, ions, water-insoluble molecules, and hormones. .... When erythrocytes are removed from circulation,

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1. You are pushing a heavy shopping cart full of water bottles with a constant force. The shopping cart has

jarptica [38.1K]

Answer:

F = 50 N

Explanation:

Given data:

Mass of car = 250 Kg

Acceleration of car = 0.20 m/s²

Force required = ?

Solution:

Formula:

F = m×a

F = applied force

m = mass

a = acceleration

Now we will put the values in formula.

F = 250 Kg × 0.20 m/s²

F = 50 Kg.m/s²

Kg.m/s² = N

F = 50 N

3 0

2 years ago

What types of atoms are in metallic bond?

Tresset [83]

If you know the Table of elements you can see it on.

3 0

3 years ago

Read 2 more answers

What does this mean: A saturated solution may be quite dilute because some substances have a very low solubility. I don't unders

atroni [7]

Answer:

Here's how I would explain it.

Explanation:

Think of it this way.

When you mix solutions of silver nitrate and sodium chloride, you get an immediate precipitate of silver chloride. The equation is

Ag⁺(aq) + Cl⁻(aq) ⟶ AgCl(s)

Now, take some AgCl and stir it vigorously with water.

You won't see much happening, because the AgCl is has such a low solubility. Not much of it will go into solution. And yet, a small amount of it does dissolve until the solution is saturated.

The concentration of AgCl in the saturated solution is

about 0.000 01 mol·L⁻¹.

I hope you will agree that this is a dilute solution even though it is saturated with AgCl.

8 0

3 years ago

Select all of the following statements that are false about ΔGo and ΔG:a) If the reaction has a large negative ΔGo value, the re

OLEGan [10]

Answer:

a) If the reaction has a large negative ΔGo value, the reaction must reach equilibrium at a small extent of reaction value

d) ΔGo and ΔG have the same magnitude, they just have opposite signs.

Explanation:

The fraction of the total heat energy if a system that does useful work is known as Gibb's free energy (G) and the change from the initial to final state is designated by $\Delta G$ . It is observed that the values of $\Delta G$ changes with experimental conditions such as temperature , pressure , concentration etc.

$\Delta G^0$ is the standard free energy change which is a balance of two natural tendencies of any system.

Minimization of potential energy or enthalpic factor $\Delta H^0$

Maximization of disorderliness or entropic factor $T\Delta S^0$

Mathematically; $\Delta G$ = $\Delta H^0$ - $T\Delta S^0$

Thus; from above mentioned, the statements that are true about ΔG⁰ and ΔG are:

ΔG⁰ and ΔG can have different values, they don't even have to have the same sign

For a reaction that reaches equilibrium, the minimum value of free energy must be at the equilibrium point

If ΔG⁰ , measured at an extent of reaction = 0.5, is positive, the sign for ΔG when the extent of reaction = 0.80 is also positive.

while the false statements include:

a) If the reaction has a large negative ΔG⁰ value, the reaction must reach equilibrium at a small extent of reaction value

d) ΔG⁰ and ΔG have the same magnitude, they just have opposite signs.

7 0

3 years ago

Albus Dumbledore provides his students with a sample of 19.3 g of sodium sulfate. How many oxygen atoms are in this sample

Dimas [21]

Answer:

3.27·10²³ atoms of O

Explanation:

To figure out the amount of oxygen atoms in this sample, we must first evaluate the sample.

The chemical formula for sodium sulfate is Na₂SO₄, and its molar mass is approximately 142.05 $\frac{g}{mol}$ .

We will use stoichiometry to convert from our mass of Na₂SO₄ to moles of Na₂SO₄, and then from moles of Na₂SO₄ to moles of O using the mole ratio; then finally, we will convert from moles of O to atoms of O using Avogadro's constant.

19.3g Na₂SO₄ · $\frac{1 mol Na^2SO^4}{142.05g Na^2SO^4}$ · $\frac{4 mol O}{1 mol Na^2SO^4}$ · $\frac{6.022x10^2^3}{1 mol O}$

After doing the math for this dimensional analysis, you should get a quantity of approximately 3.27·10²³ atoms of O.

3 0

3 years ago