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svetlana [45]
3 years ago
12

What is a base? chemistry

Chemistry
2 answers:
Molodets [167]3 years ago
4 0
The answer is letter B
Citrus2011 [14]3 years ago
3 0

Answer:

A base is <u><em>A. a substance that increace the concentration of OH- ions in solution.</em></u>

Explanation:

According to Arrhenius Theory, a base is any substance that, when dissolved, releases hydroxyl ions (OH–). The bases are also known as alkalis, because when the hydroxyl groups dissociate and release, the pH of the solutions increases, that is, the solution becomes alkaline. Then its pH is greater than 7.

According to the Brønsted-Lowry Theory, a base is a substance capable of accepting protons (H +) in solution.

According to Lewis Theory, the bases are also considered those substances capable of donating or transferring electrons.

So, <u><em>a base is A. a substance that increace the concentration of OH- ions in solution.</em></u>

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Why is calcium in group 2A if the modern periodic table
nasty-shy [4]
Calcium is in group 2A because it has two valence electrons and an oxidation state of 2+. Hope this is accurate & helpful! Enjoy your evening.
4 0
3 years ago
The density of water is 1 g/cm3. brent used the following method to convert 1 g/cm3 to kg/m3.
11111nata11111 [884]

Answer:

a) The wrong denominator for the equivalent fraction of kilograms to grams

b) The use of the scale factor of length rather than the scale factor of volume for the equivalent fraction of cubic centimeters to cubic meters

c) The arrival at the correct 1000 kg/m³ rather than 0.1 g/m³ based on the expression on the left of the equation

The density of water = 1 g/cm³

The given equation is presented as follows;

1 g/cm³ × 1 kg/(1000 kg) × 100 cm³/(1 m³) = 1000 kg/m³

The error in the conversion method are;

a) The conversion, 1 kg/(1,000 kg) has an error, the correct conversion is (1 kg)/1,000 g)

b) The volume conversion error, 100 cm³/(1 m³), the correct volume conversion is (100 cm)³/(1 m³) = 1,000,000 cm³/(1 m³)

c) The right of the equal to sign error; using the left side expression only, the (wrong) answer is 0.1 g/m³

The correct equation is presented as follows;

1 g/cm³ × 1 kg/(1000 g) × 1,000,000 cm³/(1 m³) = 1000 kg/m³

Explanation: hope this help.

7 0
2 years ago
Hydrogen is manufactured on an industrial scale by this sequence of reactions: Write an equation that gives the overall equilibr
RideAnS [48]

The question is incomplete. The complete question is :

Hydrogen is manufactured on an industrial scale by this sequence of reactions:

$CH_3(g) + H_2O(g) \rightleftharpoons CO(g) + 3H_2(g    ) \ \ \ \ \ \ \ \ \ \ K_1$

$CO(g) + H_2O(g) \rightleftharpoons CO_2(g) + H_2(g) \ \ \ \ \ \ \ \ \ \ \ \  K_2$

The net reaction is  :

$CH_4(g) + 2H_2O(g) \rightleftharpoons CO_2(g) + 4H_2(g) \ \ \ \ \ \ \ \ \ K$

Write an equation that gives the overall equilibrium constant K in terms of the equilibrium constants K_1 and K_2. If you need to include any physical constants, be sure you use their standard symbols, which you'll find in the ALEKS Calculator.

Solution :

$CH_3(g) + H_2O(g) \rightleftharpoons CO(g) + 3H_2(g    ) \ \ \ \ \ \ \ \ \ \ K_1$

$K_1 = \frac{[CO][H_2]^3}{[CH_4][H_2O]}$     ...............(1)

$CO(g) + H_2O(g) \rightleftharpoons CO_2(g) + H_2(g) \ \ \ \ \ \ \ \ \ \ \ \  K_2$

$K_2 = \frac{[CO_2][H_2]}{[CO][H_2O]}$  ...................(2)

$CH_4(g) + 2H_2O(g) \rightleftharpoons CO_2(g) + 4H_2(g) \ \ \ \ \ \ \ \ \ K$

$K=\frac{[CO_2][H_2]^4}{[CH_4][H_2O]^2}$

On multiplication of equation (1) and (2), we get

$K_1 \times K_2=\frac{[CO][H_2]^3}{[CH_4][H_2O]} \times \frac{[CO_2][H_2]}{[CO][H_2O]}$

$K_1K_2=\frac{[CO_2][H_2]^4}{[CH_4][H_2O]^2}$  .................(4)

Comparing equation (3) and equation (4), we get

$K=K_1K_2$

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3 years ago
How many electron(s) is (are) needed to complete hydrogen's outer shell.
Effectus [21]
Two electrons are needed to complete hydrogen's outer shell.
3 0
3 years ago
In which situation has the independent variable for the experiment been changed?
ki77a [65]
Idk cause I’m not completely sure I apologize
7 0
3 years ago
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