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yan [13]
3 years ago
10

What kind of bond is present in HCI? (Use the electronegativity values from

Chemistry
1 answer:
Snezhnost [94]3 years ago
8 0
The answer is
D. Covalent bond
Hope this helps you have a great day.
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A solution contains 15 ppm of benzene. The density of the solution is 1.00 g/mL. This means that ________.
snow_tiger [21]

Answer:

  • second choice:<em><u> 1.0 g of the solution contains 15 × 10⁻⁶ g of benzene.</u></em>

Explanation:

ppm is a unit of concentration that means parts per million. In grams that is grams of solute per one million (10⁶) grams of solution.

Then, <em>15 ppm of benzene</em> means that there are 15 grams of benzen in 1,000,000 grams of solution.

That leads to:

  • 1,000,000 g solution / 15 g benzene

Multiplying numerator and denominator by 10⁻⁶ you find:

  • 1,000,000 × 10⁻⁶ g solution / (15 × 10⁻⁶ g benzene)

Simplifying:

  • 1.0 g solution / (15 × 10⁻⁶ g benzene)

Which is read as 1.0 g of the solution contains 15 × 10⁻⁶ g of benzene, i.e. the second answer choice.

6 0
3 years ago
Juanita dissolves 46 g of MgBr2 (molar mass: 184.11 g/mol) in 0.5 kg of distilled water. What is the molality of the solution?
irina [24]
Formula: molality, m = n solute / kg solvent

n solute = # of moles of solute = mass(g) / molar mass

Molar mass of Mg Br2 = 184.11 g/mol

m = [46g / 184.11 g/mol] / 0.5 kg = 0.50 mol/kg
3 0
3 years ago
Methane is the chemical that is most abundant in natural gas.<br> a. True<br> b. False
aliya0001 [1]
<span>a. True. Methane is the chemical that is most abundant in natural gas. </span>

3 0
3 years ago
Suppose there is 0.63 g of HNO3 per 100 mL of a particular solution. What is the concentration of the HNO3 solution in moles per
Vadim26 [7]

Answer:

There are 0.09996826 moles per liter of the solution.

Explanation:

Molar mass of HNO3: 63.02

Convert grams to moles

0.63 grams/ 63.02= 0.009996826

Convert mL to L and place under moles (mol/L)

100mL=0.1 L

0.009996826/0.1= 0.09996826 mol/L

4 0
3 years ago
What is the potential energy of a 2 kg plant that is on a windowsill 1.3 m high
gulaghasi [49]

Answer:

P.E = 25.48 J

Explanation:

Given data:

Mass = 2 Kg

Height = 1.3 m

Potential energy = ?

Solution:

Formula:

P.E = m . g . h

P. E = potential energy

m = mass in kilogram

g = acceleration due to gravity

h = height

Now we will put the values in formula.

P.E = m . g . h

P.E = 2 Kg . 9.8 m /s² . 1.3 m

P.E = 25.48 Kg. m² / s²

 Kg. m² / s² = J

P.E = 25.48 J

8 0
3 years ago
Read 2 more answers
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