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Sedbober [7]
2 years ago
15

Three currents are passing through a surface bounded by a closed path. The currents have different values and directions. Accord

ing to Ampere’s law, (Equation 21.8), what is the value of I on the right side of this equation?
Physics
1 answer:
GaryK [48]2 years ago
7 0

Answer:

See Explanation Below

Explanation:

This question is incomplete.

I'll answer this question on general terms. You'll get your result if you apply the steps I'll highlight below.

To start with; what's Ampere law;

It states that for any closed loop path, the sum of the length elements times the magnetic field in the direction of the length element is equal to the permeability times the electric current enclosed in the loop.

The simple translation of this law is that, the sum of current in the close loop gives us the desired result.

Rephrasing your question;

Three currents, (I1 = +3A, I2 = +4A and I3 = -5A) are passing through a surface bounded by a closed path. The currents have different values and directions. According to Ampere’s law, what is the value of I on the right side of this equation?

First, we take note of the signs in front of the given currents.

The negative sign in front of I3 means that; it is moving in opposite direction of I1 and I2.

To calculate the value of I.

The value of I is the sum of the three currents:

i.e. 3A + 4A - 5A

I = 2 A

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The peak value of an alternating current in a 1500-W device is 6.4 A. What is the rms voltage across it
horrorfan [7]

Answer:

6787.5 V

Explanation:

From the question,

P = IV..................... Equation 1

Where P = Power, I = rms current, V = rms voltage.

make V the subject of the equation

V = P/I................. Equation 2

Given: P = 1500 W, I = 6.4/√2 = 4.525 A

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A square loop of wire is held in a uniform 0.24 T magnetic field directed perpendicular to the plane of the loop. The length of
NNADVOKAT [17]

Answer:

Explanation:

Given that,

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dL/dt = 5.4cm/s = 0.054m/s

Since it is decreasing

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When L is 14cm, what is the EMF induced?

L = 14cm = 0.14m

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ε = - dΦ/dt

Where flux is given as

Φ = BA

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Then, Φ = BL²

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ε = - dΦ/dt

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<u>Answer</u>

D. 1,500 m/s

<u>Explanation</u>

the wave equation states that,

V = λf

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