Question

Bubbles of H2 form when metal D is placed in hot H₂O. No reaction occurs when D is placed in a solution of a salt of metal E, but D is discolored and coated immediately when placed in a solution of a salt of metal F. What happens if E is placed in a solution of a salt of metal F? Rank metals D, E, and F in order of increasing reducing strength.

Answer 1

The order of reducing strength are as follow

E > D > F .

Since there is no reaction with D and salt of E it indicates that D is less reactive than the E. When D react with the salt F , a reaction take place which indicates that D is more reactive than F.

So reactivity can be given in the order

E > D > F .

So, F is least reactive so it neither displace E nor D

So, in first reaction

Metal F + Salt of E ------ No reaction will be observed

No reaction is observed between metal F and salt E

B) As we founded that E is more reactive than D and, D react with H2O

E is also get to react with H2O.

Thus, the order of reducing strength are as follow

E > D > F .

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