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olga nikolaevna [1]
3 years ago
6

When H2SO4 is added to PbI2, a precipitate of PbSO4 forms. The PbSO4 is then filtered from the solution, dried, and weighed. If

the recovered PbSO4 is found to have a mass of 0.0471 g, how many moles of iodide ions were in the original solution?
Chemistry
1 answer:
Nookie1986 [14]3 years ago
3 0

Answer:

n_{I^-}=3.11x10^{-4}molI^-

Explanation:

Hello,

In this case, the undergoing chemical reaction is shown below:

H_2SO_4(aq)+PbI_2(aq)\rightarrow PbSO_4(s)+2HI(aq)

Thus, we obtain 0.0471 g of lead (II) sulfate, the iodide ions  in the original solution are computed below by stoichiometry, taking into account that into 1 mole of lead (II) iodide there are 2 moles of iodide ions:

n_{I^-}=0.0471gPbSO_4*\frac{1molPbSO_4}{303.26gPbSO_4}*\frac{1molPbI_2}{1molPbSO_4}*\frac{2molI^-}{1molPbI_2} \\n_{I^-}=3.11x10^{-4}molI^-

Best regards.

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anyanavicka [17]

Answer:

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Explanation:

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6 0
3 years ago
How many grams of nitric acid will react completely with a block of iron metal that is 4.5 cm by 3.0 cm by 3.5 cm, if the densit
denpristay [2]

Balance the equation first: 

2 Fe+6 HNO3→2 Fe(NO3)3+3H2

Then calculate mass of Iron :

4.5×3.0×3.5 cm3(1 mL1 cm3)(7.87 g Fe1 ml)=371.86 g Fe

Now use Stoichiometry:

371.86 g Fe×(1 mol Fe55.85 g Fe)×(6 mol HNO32 mol Fe)=19.97 mol HNO3

Convert moles of nitric acid to grams

19.97 mol HNO3×(63.01 g HNO31 mol HNO3)=1258.3 g HNO3



7 0
3 years ago
Read 2 more answers
Instead of 6 M NaOH being added to the solution, 6 M HCl is added. How will this affect the test for the presence of ammonium io
Lera25 [3.4K]

Answer:

Ammonia gas(an alkaline gas with characteristics of choking or irritating smell) is not liberated when 6mole of HCl is added to the solution instead of 6mole of NaOH, to test for the presence of ammonium ion in the solution

Explanation:

As expected, when testing for ammonium ion in a solution (precisely ammonium salt solution), Sodium Hydroxide (NaOH) is required as the test reagent.

When NaOH is added to the solution, A gas with characteristics of choking or irritating smell is liberated.

This gas turn red litmus paper blue.

This liberated gas is an alkaline gas, which is confirmed as an ammonia gas(NH3).

If HCl is added instead of NaOH, the ammonia gas will not be liberated, which indicates that the test reagent used is wrong.

3 0
3 years ago
Say I grab a bunch of aluminum foil (9.5g) and ball it up. Aluminum has a specific heat of .9J/g*C. How much would the aluminum’
Brrunno [24]

Answer:

ΔT = 0.78 °C

Explanation:

Given data:

Mass of Al = 9.5 g

Specific heat capacity of Al = 0.9 J/g.°C

Temperature change = ?

Heat added = 67 J

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

67 J = 9.5 g × 0.9 j/g.°C × ΔT

67 J = 85.5 j/°C × ΔT

ΔT = 67 J  /  85.5 j/°C

ΔT = 0.78 °C

7 0
3 years ago
Why the copper is able to replace the silver, but the reverse reaction will not result in a replacement reaction?
PSYCHO15rus [73]

Answer:

Copper is more reactive and higher in the activity series

Explanation:

Copper is able to replace the silver in a replacement reaction because it is more reactive and higher in the activity series.

Substances or ions that are higher in the activity series are typically more reactive than those ones below them.

In like manner, they are able to replace the lowers ones in a chemical reaction due to their higher reactivity potential.

A less reactive element and a lower one in the activity series cannot displace a higher one in the series.

7 0
3 years ago
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