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2 years ago

What indicators of a chemical reaction occurred in the following equation?

Chemistry

1 answer:

ch4aika [34]2 years ago

6 0

Answer:

1) evolution of gas

2) evolution of heat

Explanation:

In this reaction, glucose is broken down into its constituents; carbon dioxide and water. The question is to decipher indicators of a chemical reaction from the equation.

If we look at the equation carefully, we will notice that a gas was evolved (CO2). The evolution of a gas indicates that a chemical reaction must have taken place. Secondly, energy is given off as heat. This is another indication that a chemical reaction has taken place.

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How does the density of a gas depend on the molar mass of the gas?

AlladinOne [14]

Answer:

The density of the ideal gas is directly proportional to its molar mass.

Explanation:

Density is a scalar quantity that is denoted by the symbol ρ (rho). It is defined as the ratio of the mass (m) of the given sample and the total volume (V) of the sample.

$\rho = \frac{m}{V}$ ......equation (1)

According to the ideal gas law for ideal gas:

$PV = nRT$ ......equation (2)

Here, V is the volume of gas, P is the pressure of gas, T is the absolute temperature, R is Gas constant and n is the number of moles of gas

As we know,

The number of moles: $n = \frac{m}{M}$

where m is the given mass of gas and M is the molar mass of the gas

So equation (2) can be written as:

$PV = \frac{m}{M}RT$

⇒ $PM= \frac{m}{V} RT$

⇒ $\frac{PM}{RT}= \frac{m}{V}$ ......equation (3)

Now from equation (1) and (3), we get

$\frac{PM}{RT}= \frac{m}{V} = \rho$

⇒ Density of an ideal gas: $\rho = \frac{PM}{RT}$

⇒ <em>Density of an ideal gas: ρ ∝ molar mass of gas: M</em>

<u>Therefore, the density of the ideal gas is directly proportional to its molar mass. </u>

6 0

3 years ago

Calculate the value of the equilibrium constant, Kc, for the reaction below, if 0.208 moles of sulfur dioxide gas, 0.208 moles o

Harman [31]

First, we convert the moles of each substance into the concentration using the volume of the reactor.
[SO₃] = 0.425/1.5 = 0.283 M
[SO₂] = 0.208 / 1.5 = 0.139 M
[O₂] = 0.208/1.5 = 0.139 M
The equilibrium constant is calculated by:
Kc = [SO₃]² / [O₂][SO₂]²
Kc = (0.283)²/(0.139)(0.139)²
Kc = 29.8 = 2.98 x 10¹

The answer is C

8 0

3 years ago

Please help 21 points

Novosadov [1.4K]

Answer:

You

Explanation:

Will have to fill in the graph organizer with a story

4 0

2 years ago

a cube of iron (cp = 0.450 j/g•°c) with a mass of 55.8 g is heated from 25.0°c to 49.0°c. how much heat is required for this pro

krek1111 [17]