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Zinaida [17]
2 years ago
7

What indicators of a chemical reaction occurred in the following equation?

Chemistry
1 answer:
ch4aika [34]2 years ago
6 0

Answer:

1) evolution of gas

2) evolution of heat

Explanation:

In this reaction, glucose is broken down into its constituents; carbon dioxide and water. The question is to decipher indicators of a chemical reaction from the equation.

If we look at the equation carefully, we will notice that a gas was evolved (CO2). The evolution of a gas indicates that a chemical reaction must have taken place. Secondly, energy is given off as heat. This is another indication that a chemical reaction has taken place.

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<u>We are given:</u>

M1 = 3 Molar        V1 = 80 mL

M2 = x Molar        V2 = 100 mL

<u>Finding the molarity:</u>

We know that:

M₁V₁ = M₂V₂

where V can be in any units

(3)(80) = (x)(100)

x = 240/100                                          [dividing both sides by 100]

x = 2.4 Molar

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2 years ago
Materials move across a cell membrane in a process called _______.
maxonik [38]

Answer:

Diffusion

Explanation:

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Answer:

I don’t want to download a pdf that I don’t know what it is…

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3 years ago
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Absolute zero is what temperature on the fahrenheit scale?
vampirchik [111]

Answer:

  • Absolute zero is - 459.67 °F

Explanation:

<u>1) Convert absolute zero to celsius:</u>

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<u>2) Convert - 273.15°C to Fahrenheit:</u>

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8 0
2 years ago
How many moles are present in
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Answer: (a) There are 0.428 moles present in 12 g of N_{2} molecule.

(b) There are 2 moles present in 12.044 \times 10^{23} particles of oxygen.

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(a). The mass of nitrogen molecule is given as 12 g.

As the molar mass of N_{2} is 28 g/mol so its number of moles are calculated as follows.

No. of moles = \frac{mass}{molar mass}\\= \frac{12 g}{28 g/mol}\\= 0.428 mol

So, there are 0.428 moles present in 12 g of N_{2} molecule.

(b). According to the mole concept, 1 mole of every substance contains 6.022 \times 10^{23} atoms.

Therefore, moles present in 12.044 \times 10^{23} particles are calculated as follows.

Moles = \frac{12.044 \times 10^{23}}{6.022 \times 10^{23}}\\= 2 mol

So, there are 2 moles present in 12.044 \times 10^{23} particles of oxygen.

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