The limiting reagent when 5 g of NaOH and 4.4 g CO₂ allowed to react will be NaOH
<h3>What is Limiting reagent ?</h3>
The limiting reactant (or limiting reagent) is the reactant that gets consumed first in a chemical reaction and therefore limits how much product can be formed.
Given chemical equation in balanced form ;
2NaOH(s) + CO₂(g) → Na₂CO₃(s) + H₂O(l).
According to the Chemical equation ;
- The limiting reagent when 5 g of NaOH and 4.4 g CO₂ allowed to react will be NaOH
If 44 g CO₂ requires 80 g of NaOH, therefore, 4.4 g CO₂ will require atleast 8 g of NaOH.
But the available quantity is 5 g NaOH. thus, NaOH is the Limiting reagent.
- 6.625 g of Na₂CO₃ are expected to be produced 5.0 g of NaOH and 4.4 g of CO₂ are allowed to react
As 80 g NaOH produces 106 g of Na₂CO₃.
Therefore 5 g NaoH will produce ;
106 / 80 x 5 = 6.625 g
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Answer: 0.5 kg
Explanation:
Force of launched skyrocket = 10 N
Acceleration of skyrocket = 20 m/s squared (i.e 20m/s^2)
Mass of the skyrocket = ?
Recall that Force is the product of the mass of an object by the acceleration by which it moves.
i.e Force = Mass x Acceleration
10N = Mass x 20m/s^2
Mass = (10N/20m/s^2)
Mass = 0.5 kg
Thus, the mass of this skyrocket is 0.5 kilograms
D is the answer I believe.
Answer:
40 C atoms
Explanation:
Step 1: Write organic compound
10C₄H₁₀
We see here that in 1 mol of C₄H₁₀, we would have 4 atoms of C.
We are given that we have 10 moles of C₄H₁₀.
Therefore, we have 4 · 10 = 40 atoms C
Temperature of gas at volume of 950 cm³ is 368.14K or 94.99⁰c.
- Volume is the amount of space a three-dimensional object takes up, expressed in cubic units.
- units of volume are mL, liter, cm³ or m³.
Given,
in this question, volume occupied by gas at 10.9⁰c is 733cm³.
we have to find out temperature at which gas occupies volume of 950 cm³.
First, convert temperature from celcius to Kelvin
10.9⁰c = 10.9 + 273.15 = 284.05 K
By equation or Boyle's Law
P1 x V1 / T1 = P2 x V2 / T2
Pressure is constant here
therefore, V1 / T1 = V2 / T2
here, V1 = 733 cm³
T1 = 284.05 K
V2 = 950 cm³
we have to find out T2
So, 733 / 284.05 = 950 / T2
T2 = 284.05 × 950 / 733 = 368.14 K
= 94. 99⁰c
Therefore the temperature of gas at volume of 950 cm³ is 368.14K or 94.99⁰c.
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