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diamong [38]
3 years ago
6

Two force vectors are oriented such that the angle between their directions is 38 degrees and they have the same magnitude. If t

heir magnitudes are 1.84 newtons, then what is the magnitude of their sum?
Physics
1 answer:
Usimov [2.4K]3 years ago
6 0

Answer:

Sum of the forces will be equal to 3.479 N

Explanation:

We have given two same forces are oriented at an angle of 38°

Magnitude of each force is given F_1=F_2=1.84

We have to find the sum of the forces

Sum of the forces will be equal to

F=\sqrt{F_1^2+F_2^2+2F_1F_2cos\Theta }

So sum of the forces will be equal to F=\sqrt{1.84^2+1.84^2+2\times 1.84\times 1.84\times cos38^{\circ} }=3.479

So sum of the force will be equal to 3.479 N

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A projectile is fired with an initial velocity of 120.0 meters per second at an angle, θ above the horizontal. If the projectile
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Answer:

θ = 62.72°

Explanation:

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v₀x: Initial speed in x  in m/s

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vfy= v₀y -gt Formula (3)

Where:  

y: vertical position in meters (m)  

y₀ : initial vertical position in meters (m)  

t : time in seconds (s)

v₀y: initial  vertical velocity  in m/s  

vfy: final  vertical velocity  in m/s  

g: acceleration due to gravity in m/s²

Data

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v₀x= 55 m/s

x-y components of the initial  velocity ( v₀)

v₀x = v₀*cosθ Equation (1)

v₀y = v₀*sinθ   Equation (2)

Calculating of the angle θ

We replace data in the  Equation (1)

55 =  120*cosθ

cosθ = 55 / 120

\theta = cos^{-1}(  \frac{55}{120} )

θ = 62.72°

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