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Maurinko [17]
3 years ago
15

Hannah has information about an object in circular orbit around Earth.

Physics
2 answers:
Svetllana [295]3 years ago
4 0
The distance of the orbiting object to Earth will give Hannah the radius which she needs.
Elena-2011 [213]3 years ago
3 0

The correct answer is:

the distance of the orbiting object to Earth.

In fact, we know that the gravitational force that keeps the object in circular motion around the Earth is equal to the centripetal force, so we can write:

G\frac{Mm}{r^2}=m\frac{v^2}{r}

If we re-arrange the equation, we find an expression for the tangential speed of the object:

v=\sqrt{\frac{GM}{r}}

and we see that it depends on 3 quantities: G, M (the mass of the Earth) and r (the distance of the object from the Earth).

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The eyepiece of a compound microscope has a focal length of 2.70 cm , and the objective lens has f = 0.750 cm . If an object is
skad [1K]

Answer:

Explanation:

Image formation by objective lens ,

f = focal length of objective = .75 cm, ( positive )

object distance u = .81 cm ( negative )

v = image distance  

1/v - 1/u = 1/f

1/v + 1/.81 = 1 / .75

1/v = 1/ .75 - 1/.81 = .098765

v = 10.125.cm

Image formation by eye piece,

v = infinity ( for relaxed eye )

f ( eye piece ) = 2.70cm

u = ?

1/v - 1/u = 1/f

0 -1/u = 1/2.7

u = 2.7 cm

Total length  between lenses

= 2.7 + 10.125

= 12.825 cm

Total magnification = m₁ x m₂

m₁ is magnification by objective and m₂ is magnification by eye piece

m₁ = v/u = 10.125 / .810 = 12.5

m₂ =  1 + D / f = 1 + 25 / 2.7 = 10.25

Total magnification

= 12.5 x 10.25 = 128.125

7 0
3 years ago
Imagine you want to design a toy boat from a block of clay. What would you need to consider to make sure that your boat can floa
Nikitich [7]
In the bottom of the boat, make tiny airtight holes to keep it afloat.
5 0
3 years ago
Which of the following is NOT a characteristic of electromagnetic light waves?
bearhunter [10]

Answer:

A. They can be reflected and refracted

3 0
3 years ago
. In a common test for cardiac function (the “stress test”), the patient walks on an
Alex

The power required from a 75-kg patient when the treadmill is sloping at required speed is 131.58 W.

<h3>Parallel force on the patient</h3>

The parallel force on the patient is calculated as follows;

F = mg sinθ

F = (75 x 9.8) x sin(12)

F = 152.82 N

<h3>Average power required </h3>

P = FV

where;

  • V is speed  = 3.1 km/h = 3.1/3.6 = 0.861 m/s

F = 152.82 x 0.861

F = 131.58 W

Thus, the power required from a 75-kg patient when the treadmill is sloping at required speed is 131.58 W.

Learn more about average power here: brainly.com/question/19415290

#SPJ1

6 0
2 years ago
The nucleus of a cell is like the ____ of a large animal.
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It is either the brain or the stomach.
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3 years ago
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