Answer:
Explanation:
Image formation by objective lens ,
f = focal length of objective = .75 cm, ( positive )
object distance u = .81 cm ( negative )
v = image distance
1/v - 1/u = 1/f
1/v + 1/.81 = 1 / .75
1/v = 1/ .75 - 1/.81 = .098765
v = 10.125.cm
Image formation by eye piece,
v = infinity ( for relaxed eye )
f ( eye piece ) = 2.70cm
u = ?
1/v - 1/u = 1/f
0 -1/u = 1/2.7
u = 2.7 cm
Total length between lenses
= 2.7 + 10.125
= 12.825 cm
Total magnification = m₁ x m₂
m₁ is magnification by objective and m₂ is magnification by eye piece
m₁ = v/u = 10.125 / .810 = 12.5
m₂ = 1 + D / f = 1 + 25 / 2.7 = 10.25
Total magnification
= 12.5 x 10.25 = 128.125
In the bottom of the boat, make tiny airtight holes to keep it afloat.
Answer:
A. They can be reflected and refracted
The power required from a 75-kg patient when the treadmill is sloping at required speed is 131.58 W.
<h3>Parallel force on the patient</h3>
The parallel force on the patient is calculated as follows;
F = mg sinθ
F = (75 x 9.8) x sin(12)
F = 152.82 N
<h3>Average power required </h3>
P = FV
where;
- V is speed = 3.1 km/h = 3.1/3.6 = 0.861 m/s
F = 152.82 x 0.861
F = 131.58 W
Thus, the power required from a 75-kg patient when the treadmill is sloping at required speed is 131.58 W.
Learn more about average power here: brainly.com/question/19415290
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