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Maurinko [17]
3 years ago
15

Hannah has information about an object in circular orbit around Earth.

Physics
2 answers:
Svetllana [295]3 years ago
4 0
The distance of the orbiting object to Earth will give Hannah the radius which she needs.
Elena-2011 [213]3 years ago
3 0

The correct answer is:

the distance of the orbiting object to Earth.

In fact, we know that the gravitational force that keeps the object in circular motion around the Earth is equal to the centripetal force, so we can write:

G\frac{Mm}{r^2}=m\frac{v^2}{r}

If we re-arrange the equation, we find an expression for the tangential speed of the object:

v=\sqrt{\frac{GM}{r}}

and we see that it depends on 3 quantities: G, M (the mass of the Earth) and r (the distance of the object from the Earth).

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A Jeep accelerated at 2.2 m/s2 until after 18 seconds its displacement was 660 meters. Assuming the Jeep traveled in a straight
pogonyaev
Ok so we know:
The time (t) is 18seconds
The acceleration (a) is 2.2m/s2
The displacement (r) is 660

Using the equation
r = ut +  \frac{1}{2} a {t}^{2}
With 'u' being the initial velocity we want, we get:
660 = 18u + 356.4
So:
18u = 303.6
So:
u = 16.8666
So the original/initial velocity was 16.8666 or 16.87 m/s

Hope this helped

5 0
3 years ago
The cube has a mass of 72.9 g
disa [49]
Is that on the question or ?
4 0
3 years ago
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4 0
3 years ago
The speed of a 2 kg mass on a spring is 5 m/s as it passes through its equilibrium position. What is its frequency if the amplit
Lena [83]

Solution :

Given :

Mass of the object attached to the spring, m = 2 kg

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We known,

$V_{max} = \omega A = 2 \pi f A$

Therefore, $f= \frac{V_{max}}{2 \pi A}$

$f= \frac{5}{2 \times 3.14 \times 2.5}$

f   = 0.32 Hz

Therefore the frequency of the object is 0.32 hertz when the amplitude of the 2 kg mass is 2.5 m moving a speed of 5 m/s.

3 0
2 years ago
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