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mote1985 [20]
2 years ago
15

At what point should a business information manager assume that he or she will not receive any more new questions or requests to

solve problems?
A.
Questions and problem-solving requests usually end after about six weeks.

B.
It can take six months or more for a business information manager to stop receiving questions or requests.

C.
It takes about a year before the manager has answered all questions and solved all problems.

D.
There are always new questions to answer and new problems to solve in this line of work.
Physics
1 answer:
stealth61 [152]2 years ago
7 0

There are always new questions to answer and new problems to solve in this area. The correct option is D.

<h3>Why is problem solving essential in business?</h3>

It is a necessary skill for supervisors and other senior positions. Individuals who have excellent problem-solving skills are a precious and considered reliable attribute in any team.

They are the ones who come up with new ideas, better ways of operating, make things easier to understand, or help customers save time and money.

Before attempting to solve a problem, ascertain whether it is truly a problem. In addition to you, but additionally to those who are affected.

In this line of work, there are always fresh questions to answer and problems to solve.

Thus, the correct option is D.

For more details regarding problem solving, visit:

brainly.com/question/3418829

#SPJ1

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A uniform solid disk rolls without slipping down an incline making an angle θ with the horizontal. What is its acceleration? (En
Maru [420]

Answer:

aCM = (2/3)*g*Sin θ

Explanation:

Consider a uniform solid disk having mass M,  radius R and rotational inertia I  about its center of mass, rolling without  slipping down an inclined plane.

In order to get the linear acceleration of the object’s center of mass, aCM ,

down the incline,  we analyze this as follows:

The force of gravity (W = Mg) acting straight down  is resolved into components parallel and  perpendicular to the incline.

Since the object rolls without  slipping there is a force of  friction (Ff) acting on the object,  at it’s point of contact with the  incline, in the direction up  the incline.

Newton’s 2nd Law gives then for acceleration down the incline

∑Fx' = m*aCM   ⇒    m*g*Sin θ - Ff = m*aCM

The force of friction also causes a torque around the center of mass

having lever arm R so we can also write

τ = R*Ff = I*α

Solving for the friction,    Ff = I*α / R

This is used in the expression  derived from the 2nd Law:

m*g*Sin θ - Ff = m*g*Sin θ - (I*α / R) = m*aCM

The objects angular acceleration is related to the linear acceleration  of the edge that contacts the incline by

a = R*α

Since the object rolls without  slipping this has the same  magnitude as aCM so we have  that

α = aCM / R

Using this in

m*g*Sin θ - (I*α / R) = m*g*Sin θ - (I*(aCM / R) / R) = m*aCM

⇒  aCM = (m*g*Sin θ*R²) / (I + m*R²)

if I = (1/2)*m*R²   (for a uniform solid disk)

we get

aCM = (2/3)*g*Sin θ

6 0
3 years ago
Hurricanes are least likely to form in which of the following?
Sholpan [36]
The best and most correct answer among the choices provided by the question is the second choice "Lake Michigan"


A hurricane<span> is a storm that occurs in the </span>Atlantic Ocean <span>and northeastern Pacific </span>Ocean<span>, a typhoon occurs in the northwestern Pacific </span>Ocean<span>, and a cyclone occurs in the south Pacific or Indian </span>Ocean<span>. Tropical cyclones can be categorized by intensity.</span>

I hope my answer has come to your help. God bless and have a nice day ahead!
3 0
4 years ago
If an element is a semi-conductor, which classification correctly describes it?
stiks02 [169]

Metal

Explanation:

semiconductors are materials which have a conductivity between conductors (generally metals)

8 0
3 years ago
552000 in scientific notation
LUCKY_DIMON [66]
5.52 × 10 to the 5th power (100000)  . In scientific notation you need to have a decimal numver times 10 to the power of something so you can divide 552000 by 10  5  times. So in order to get 552000 you need to have 10 to the 4th power and 5.52
4 0
3 years ago
By how much does the volume of an aluminum cube 4.00 cm on an edge increase when the cube is heated from 19.0°C to 67.0°C? The l
Genrish500 [490]

Answer:

The volume of an aluminum cube is 0.212 cm³.

Explanation:

Given that,

Edge of cube = 4.00 cm

Initial temperature = 19.0°C

Final temperature = 67.0°C

linear expansion coefficient \alpha=23.0\times10^{-6}/C^{\circ}

We need to calculate the volume expansion coefficient

Using formula of  volume expansion coefficient

\beta=3\alpha

Put the value into the formula

\beta=3\times23.0\times10^{-6}

\beta=0.000069=69\times10^{-6}/C^{\circ}

We need to calculate the volume

V= a^3

V=4^3

V=64\ cm^3

The change temperature of the cube is

\Delta T=T_{f}-T_{i}

Put the value into the formula

\Delta T=67-19 = 48^{\circ}C

We need to calculate the increases volume

Using formula of increases volume

\Delta V=V\beta\Delta T

Put the value into the formula

\Delta V=64\times69\times10^{-6}\times48

\Delta V=0.212\ cm^3

Hence, The volume of an aluminum cube is 0.212 cm³.

5 0
3 years ago
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