Two lab carts are on a frictionless track, attached by a spring. The carts are pushed together by a student in a Physics lab, co
2 answers:
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Answer:
The magnitudes of the second force is
The magnitudes of the resultant force is
Explanation:
From the question we are told that
The force is
The angle made with second force
The angle between the resultant force and the first force
For us to solve problem we are going to assume that
The magnitude of the second force is Z N
The magnitude of the resultant force is R N
According to Sine rule
Substituting values
According to cosine rule
Substituting values
Answer:
0.29D
Explanation:
Given that
F = G M m / r2
F = GM(6m) / (D-r)2
G Mm/r2 = GM(6m) / (D-r)2
1/r2 = 6 / (D-r)2
r = D / (Ö6 + 1)
r = 0.29 D
See diagram in attached file
Explanation:
The given data is as follows.
height (h) = 98.0 m, speed (v) = 73.0 m/s,
Formula of height in vertical direction is as follows.
h = ,
or, t =
Now, formula for the required distance (d) is as follows.
d = vt
=
=
= 326.5 m
Thus, we can conclude that 326.5 m is the horizontal distance from the target from where should the pilot release the canister.