Answer:
342.3 g
Explanation:
From the question given above, the following data were obtained:
C = 12.011 g/mol
H = 1.00794 g/mol
O = 15.9994 g/mol
Molar mass of C₁₂H₂₂O₁₁ =?
C = 12 × 12.011 = 144.132 g
H = 22 × 1.00794 = 22.17468 g
O = 11 × 15.9994 = 175.9934 g
Total mass = 144.132 + 22.17468 + 175.9934
Total mass = 342.3 g
Answer:
Its either glucose or protien
Explanation:

- From the first mechanism, it can be seen that the Aluminum is reduced at cathode and Florine is oxidized at anode.
- The ratio of aluminium and fluorine is the ratio of their change in oxidation number, i.e. 2:3
<em><u>༒</u></em><em><u>H</u></em><em><u>O</u></em><em><u>P</u></em><em><u>E</u></em><em><u> </u></em><em><u>S</u></em><em><u>O</u></em><em><u> </u></em><em><u>I</u></em><em><u>T</u></em><em><u> </u></em><em><u>H</u></em><em><u>E</u></em><em><u>L</u></em><em><u>P</u></em><em><u>S</u></em><em><u> </u></em><em><u>Y</u></em><em><u>O</u></em><em><u>U</u></em><em><u>༒</u></em>
<em><u>༒</u></em><em><u>M</u></em><em><u>A</u></em><em><u>R</u></em><em><u>K</u></em><em><u> </u></em><em><u>M</u></em><em><u>E</u></em><em><u> </u></em><em><u>A</u></em><em><u>S</u></em><em><u> </u></em><em><u>B</u></em><em><u>R</u></em><em><u>A</u></em><em><u>I</u></em><em><u>N</u></em><em><u>L</u></em><em><u>I</u></em><em><u>E</u></em><em><u>S</u></em><em><u>T</u></em><em><u>༒</u></em>
Halogen are the most reactive due to their electronic configuration