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levacccp [35]
3 years ago
11

Food couldn’t reach the stomach without the esophagus and the _? please help only correct answers.

Chemistry
1 answer:
expeople1 [14]3 years ago
3 0
<span>Food couldn’t reach the stomach without the esophagus and the throat.</span>
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What mass of Ba3(PO4)2 is contained in 1575 mL of a 0.35 M solution of Ba3(PO4)2?
irina [24]

Answer:

= 331.81 g

Explanation:

Molarity is calculated by the formula;

Molarity = Moles/volume in liters

Therefore;

Moles = Molarity ×Volume in liters

          = 0.35 M × 1.575 L

          = 0.55125 Moles

But; Molar mass of Ba3(PO4)2 is 601.93 g/mol

Thus;

Mass = 0.55125 moles × 601.93 g/mol

         <u>= 331.81 g</u>

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Find the number of CoCl2 units present in a 0.78 mol sample.
stich3 [128]

\qquad\qquad\huge\underline{{\sf Answer}}

Here we go ~

1 mole of \sf{ COCl_2} has 6.022 × 10²³ molecules of the given compound.

So, 0.78 mole of \sf{COCl_2} will have ~

\qquad \sf  \dashrightarrow \: 0.78 \times 6.022 \times 10 {}^{23}

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2 years ago
The process of shedding feather and new ones back
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c

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