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2 years ago

Lewis structure of butane

Chemistry

1 answer:

eduard2 years ago

7 0

Answer:

This is the C4H10 Lewis structure: Butane. For Butane, we have a total of 26 valence electrons. Whenever we see the ending, "ane", we know that we're going to have Carbons and Hydrogens single bonded. That makes it a little bit easier to draw the C4H10 Lewis structure. We'll put four Carbons in a row and then we'll put Hydrogens around them. Because each Carbon needs to have four single bonds--each bond having two valence electrons, that'll give it an octet--we'll have three Hydrogens on the end Carbons and two on the center, like this. There are the three on the ends, and then we'll put two Hydrogens on the central Carbons. Next we'll place a single bond between each of the atoms to show that a pair of electrons is being shared.

So we've used all 26 valence electrons for the C4H10 Lewis structure, and we can see that each Carbon has four single bonds. Since each single bond has two valence electrons, that means that each Carbon has an octet. Each Hydrogen has a single bond, so it has two valence electrons. That means that it has a full outer shell as well. So we've used all the valence electrons that we had for C4H10 and everything has an octet..','.

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1. Find the masses of the following amounts.

In-s [12.5K]

The mass of 2.15 mol of hydrogen sulphide (H₂S) will be 73.272 gm and the mass of 3.95 × 10⁻³ mol of lead(II) iodide, (PbI₂) will be 1.82 gm

A mole is a very important unit of measurement that chemists use.

A mole of something means you have 6.023 x 10 ²³ of that thing.

For 2.15 mol of hydrogen sulphide (H₂S) :

1 mole hydrogen sulphide (H₂S) = 34.08088 grams

Therefore,

2.15 mol of hydrogen sulphide (H₂S) = 34.08088 grams x 2.15 mol

= 73.272 gm

For 3.95 × 10⁻³ mol of lead(II) iodide, (PbI₂) ;

1 mol of lead(II) iodide, (PbI₂) = 461.00894 grams

Therefore,

3.95 × 10⁻³ mol of lead(II) iodide, (PbI₂) = 461.00894 grams x 3.95 × 10⁻³ mol

= 1.82 gm

Hence,The mass of 2.15 mol of hydrogen sulphide (H₂S) will be 73.272 gm and the mass of 3.95 × 10⁻³ mol of lead(II) iodide, (PbI₂) will be 1.82 gm

Learn more about mole here ;

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7 0

2 years ago

Please list uses uses aluminium?

Fiesta28 [93]

Answer:

We use aluminum almost every day, aluminum can be used for juice boxes, chip bags, cans, foils, electronics, and even our cars have aluminum.

Explanation:

4 0

3 years ago

Read 2 more answers

In the decomposition reaction, 1 mole of water (mw = 18.015 g/mol) was produced for every mole of cuo (mw = 79.545 g/mol) produc

natita [175]

Reactives -> Products

CuO and water are products.

I found this reaction which has CuO and water as products: decomposition of Cu(OH)2.

Cu(OH)2 -> CuO + H2O

Stoichiometry calculus involve the mole proportions you can see in the reaction: When 1 mole of Cu(OH)2 reacts, 1 mole of CuO and 1 mole of H2O are formed.

Considering the molar masses:

Cu(OH)2 = 83.56 g/mol

CuO = 79.545 g/mol

H2O = 18.015 g/mol

Then: When 83.56 g of Cu(OH)2 react, 79.545 g of CuO and 18.015 g H2O are formed.

You should use that numbers in the rule of three:

79.545 g CuO __________18.015 g water

3.327 g CuO__________ x =3.327*18.015 /79.545 g water

x= 0.7535 g water

3 0

3 years ago

Which of the following statements is true of proteins?

UkoKoshka [18]

Answer:

The answer is Denaturation is reversible

Explanation:

Denaturation of proteins is the process whereby there is a disruption in the tertiary, quaternary or secondary structure of proteins which causes a conformation change in its action

denaturation is reversible, that is, the proteins can regain their native state when the denaturing influence is removed. This process can be called renaturation.

3 0

3 years ago

When salt is dissolved in water, what happens to the water

choli [55]

Answer:

When salt is dissolved in water, many physical properties change, among them the so called colligative properties:

The vapor pressure of water decreases,
The boiling point increases,
The freezing point decreases, and
Osmotic pressure appears.

Explanation:

Colligative properties are the physical properties of the solvents whose change is determined by the number of particles (moles or ions) of the solute added.

The colligative properties are: vapor pressure, boiling point, freezing point, and osmotic pressure.

Vapor pressure:

The vapor pressure is the pressure exerted by the vapor of a lquid over its surface, in a closed vessel.

The vapor pressure increases when a solute is added, because the presence of the solute causes less solvent molecules to be near the surface ready to escape to the vapor phase, which means that the vapor pressure is lower.

Boiling point:

The boiling point is the temperature at which the vapor pressure of the liquid equals the atmospheric pressure. Since we have seen that the vapor pressure of water decreases when a solute occupies part of the surface, now more temperature will be required for the water molecules reach the atmospheric pressure. So, the boiling point increases when salt is dissolved in water.

Freezing point:

The freezing point is the temperarute at which the vapor pressure of the liquid and the solid are equal. Since, the vapor pressure of water with salt is lower than that of the pure water, the vapor pressure of the liquid and solid with salt will be equal at a lower temperature. Hence, the freezing point is lower (decreases).

Osmotic pressure:

Osmotic pressure is the additional pressure that must be exerted over a solution to make that the vapor pressure of the solvent in the solution equals the vapor pressure of the pure solvent. This additional pressure is proportional to the concentration of the solute: the higher the salt concentration the higher the osmotic pressure.

6 0

3 years ago