20 + 1/3 = 120/3
Ans- 40....
Hope this helps you! :)
For 26
ST is = TU
27
2x-1=15
2x=16
X=8
1+tan^2(A) = sec^2(A) [Pythagorean Identities]
tan^2(A)cot(A) = tan(A)[tan(A)cot(A)] = tan(A)[1] = tan(A)
*see photo for complete solution*
Answer:
1 The first digit of the quotient is 3
2. 34 prizes per booth
3. 19 prizes left over
Step-by-step explanation:
We need to divide 985 by 29
29 goes into 98 3 times
29*3 = 87 with 13 left over
135 divided by 29
29*4 =116 135-116 =19
985÷29 = 34 with 19 left over