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2 years ago

What must happen for an electron to return to its original energy level from a higher energy level?

Chemistry

1 answer:

attashe74 [19]2 years ago

3 0

An electron should emit energy to return to its original energy level from a higher energy level.

<h3>What is an energy level?</h3>

Energy levels (also called electron shells) are fixed distances from the nucleus of an atom where electrons may be found.

The electron absorbs the energy and jumps to a higher energy level. In the reverse process, emission, the electron returns to the ground state by releasing the extra energy that is absorbed.

Hence, an electron should emit energy to return to its original energy level from a higher energy level.

Learn more about the energy level here:

brainly.com/question/17396431

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A sample of Francium-212 will decay to one sixteenth of its original amount after 80 minutes. What is the half-life of Francium-

lbvjy [14]

20 minutes.

The sample would lose one half the quantity of francium in each half-life.

$1/16 = 1/2^{4} = 1/2 \times1/2 \times1/2 \times1/2$

Thus a mass decrease by a factor of 16 would correspond to a period of four half-lives. It took 80 minutes for the sample to lose all these francium, therefore

$t_{1/2} = 80/4 = 20$ minutes.

6 0

3 years ago

PLS HELPA! Which procedure could be used to demonstrate that matter is conserved during a physical change?

Fudgin [204]

Answer:

im not too smart, but i would say, either b or d

Explanation:

4 0

3 years ago

Read 2 more answers

What is the volume (in dm3 of 1 mole of oxygen at 5 MPa and 200 K?

vodka [1.7K]

<u>Answer:</u> The volume of oxygen gas is $0.332dm^3$

<u>Explanation:</u>

To calculate the volume of the gas, we use the equation given by ideal gas equation:

$PV=nRT$

where,

P = pressure of the gas = 5 MPa = 5000 kPa (Conversion factor: 1 MPa = 1000 kPa)

V = Volume of gas = 3.34 L

n = number of moles of oxygen gas = 1 mole

R = Gas constant = $8.31dm^3\text{ kPa }mol^{-1}K^{-1}$

T = Temperature of the gas = 200 K

Putting values in above equation, we get:

$5000kPa\times V=1mol\times 8.31dm^3\text{ kPa }mol^{-1}K^{-1}\times 200K\\\\V=0.332dm^3$

Hence, the volume of oxygen gas is $0.332dm^3$

7 0

3 years ago

acid-catalyzed hydration of 1-methylcyclohexene gives two alcohols. The major product does not undergo oxidation, while the mino

noname [10]

Answer:

Major product does not undergo oxidation since it is a tertiary alcohol whereas minor product undergoes oxidation to ketone as it is secondary alcohol.

Explanation:

Hello,

In this case, given the attached picture, the hydration of the 1 methylcyclohexene yields to alcohols; 1-methylcyclohexan-1-ol and 1-methylcyclohexan-2-ol. Thus, since the OH in the 1-methylcyclohexan-1-ol (major product) is bonded to a tertiary carbon (bonded with other three carbon atoms) it is not able to increase the number of oxygen bonds (oxidation) as it already attained the octet whereas the 1-methylcyclohexan-2-ol (minor product) is able to undergo oxidation to ketone as the carbon bonded to it is secondary (bonded with other two carbon atoms), so one extra bond the oxygen is allowed to be formed to carbonyl.

Best regards.

7 0

3 years ago

"calculate the h+ in a solution that has a ph of 8.73"

alexdok [17]

The H+ in a solution that has a Ph of 8.73 is calculate as follows

Ph is always = - log (H+)

H+ = 10^-Ph

H+ is therefore = 10 ^- 8.73
H+ = 1.86 x10^-9 M

8 0

3 years ago