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Paha777 [63]
2 years ago
10

Draw atomic depictions similar to those in Problem 2.43 for: (b) ⁷⁹₃₄Se

Chemistry
1 answer:
Murrr4er [49]2 years ago
5 0

The mass number of the element is 79 , atomic number is 34 and number of neutron is 45

<h3>What is Atomic Number ?</h3>

The number of proton which is used to separate one element from the other element is called Atomic Number. It is denotes as symbol Z.

What is Atomic Notation ?

The atomic number is the number of proton which is present in the nucleus of an atom. It is represented as ^{A}_{Z}X.

where

X is the element

Z is the atomic number of that element.

A is the mass number of that isotope.

Now,

A = Z + N

79 = 34 + N

79 - 34 = N

45 = N

Thus from the above conclusion we can say that mass number of the element is 79 , atomic number is 34 and number of neutron is 45

Learn more about the Atomic Number here: brainly.com/question/487717

#SPJ4

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One with a few kinds is more likely to become unstable.

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A lack of biodiversity means there is a lower chance of them having traits that enable them to adapt to a changing environment. A lack of biodiversity is usually caused by humans. It could be the result of habitat loss, invasive species, overexploitation, pollution, or climate change.

5 0
2 years ago
Radio waves travel at the speed of light which is 3.00 x 10^8. How many minutes does it take for a radio message to reach saturn
ryzh [129]

Answer:

43.89 min

Explanation:

Given that:-

The speed of light = 3.00\times 10^8\ m/s

The distance = 7.9\times 10^8\ km

The conversion of distance in km to distance into m is shown below as:-

1 km = 1000 m

So,

Distance = 7.9\times 10^8\times 1000\ m=7.9\times 10^{11}\ m

The relation between speed distance and time is shown below as:-

Speed=\frac{Distance}{Time}

Thus,

3.00\times 10^8=\frac{7.9\times 10^{11}}{Time}

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Time = 2633.33 seconds

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Time=\frac{2633.33}{60}\ min=43.89\ min

3 0
3 years ago
Which of the following could be the subsh
andreev551 [17]

Answer:

2s^2 2p^2

Explanation:

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Moving on, we have boron and carbon, the remaining 2 electrons. Now, starting with boron, we're in the p-block.

That said, looking at the second period, the electron configuration for the valence shell of a group 4A element would be:

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