Answer:
69.726 amu
Explanation:
From the question given above, the following data were obtained:
Isotope A:
Mass of A = 68.926 amu
Abundance of A (A%) = 60.00%
Isotope B:
Mass of B = 70.925 amu
Abundance of B (B%) = 40.00%
Average atomic mass =?
The average atomic mass of the element can be obtained as shown below:
Average atomic mass
= [(Mass of A × A%)/100] + [(Mass of B × B%)/100]
= [(68.926 × 60)/100] + [(70.925 × 40)/100]
= 41.3556 + 28.37
= 69.726 amu
Therefore, the average atomic mass of the element is 69.726 amu
Answer: 7 atm
Explanation:
According to Dalton's Law, the total pressure is the sum of all the individual gas pressures
Hence, Ptotal = P1 + P2 + P3
Since, Gas A = 2 atm
Gas B = 1 atm
Gas B = 4 atm
Ptotal = (2 + 1 + 4) atm
Ptotal= 7 atm
Thus, the total pressure of the gas mixture is 7 atmosphere.
Later the answer is C. Luster