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Paha777 [63]
2 years ago
10

Draw atomic depictions similar to those in Problem 2.43 for: (b) ⁷⁹₃₄Se

Chemistry
1 answer:
Murrr4er [49]2 years ago
5 0

The mass number of the element is 79 , atomic number is 34 and number of neutron is 45

<h3>What is Atomic Number ?</h3>

The number of proton which is used to separate one element from the other element is called Atomic Number. It is denotes as symbol Z.

What is Atomic Notation ?

The atomic number is the number of proton which is present in the nucleus of an atom. It is represented as ^{A}_{Z}X.

where

X is the element

Z is the atomic number of that element.

A is the mass number of that isotope.

Now,

A = Z + N

79 = 34 + N

79 - 34 = N

45 = N

Thus from the above conclusion we can say that mass number of the element is 79 , atomic number is 34 and number of neutron is 45

Learn more about the Atomic Number here: brainly.com/question/487717

#SPJ4

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A student increases the temperature of a 556 cm3 balloon from 278 K to 308 K. Assuming constant pressure, what should the new vo
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The answer is:  [D]:  " 417 cm³ " .
_____________________________________________________
Explanation:  Use the formula:

V₁ /T₁= V₂ /T₂  ;

in which:  V₁ = initial volume = 556 cm³ ;
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                V₂ = final ("new") temperature = 308 K
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Since:  V₁ /T₁= V₂ /T₂ ;

We can rearrange this "equation/formula" to isolate "V₂" on one side of the equation; and then we can plug in our know values to solve for "V₂" ;
_______________________________________________________
       V₁ /T₁= V₂ /T₂  ;  Multiply EACH side of the equation by "T₂ " :

          →  T₂ (V₁ /T₁) = T₂  (V₂ /T₂) ;
______________________________
to get:

↔ T₂  (V₂ /T₂) = T₂ (V₁ /T₁) ;

     →  V₂ = T₂ (V₁ /T₁) ;
______________________________
Now, plug in our known values, to solve for "V₂" ;
______________________________
    →  V₂ = T₂ (V₁ /T₁) ;
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    →  V₂ = 308 K ( 556 cm³ /278 K)  ;
             → The units of "K" cancel to "1" ; and we have:
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    →  V₂ = 308*( 556 cm³ / 278 ) = [(208 * 556) / 278 ] cm³ ;
Note:  We will keep the units of volume as:  "cm³ ";  since all the answer choices given are in units of:  "cm³ " ; {that is, "cubic centimeters"}.

   →  [(208 * 556) / 278 ] cm³ = [ (115,648) / (278) ] cm³ ;
                                        
              → For the "(115,648)" ;  round to "3 (three significant figures)" ;
                        → "(115,648)" → rounds to:  "116,000" ;
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              →      (116,000) / (278) = 417.2661870503597122  ;
                                 → round to 3 significant figures; → "417 cm³ " ;
                                               → which corresponds with "choice [D]".
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The answer is:  [D]:  "417 cm³ " .
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