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Elenna [48]
2 years ago
10

The action of the weather conditions in altering the color, texture, composition, or form of exposed is called ___________. (A)

weathering (B) avalanche (C) erosion
Chemistry
1 answer:
balu736 [363]2 years ago
3 0

Answer:

Explanation:

YES BECAUSE YE SIS YES WHEN YES=\sqrt{x} x^{2} x^{2} \neq \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right]

GAMER MOMENT FROM LUIGI FOR⇔\sqrt{x} x^{2} x^{2} \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \alpha \alpha \alpha x_{123} \frac{x}{y} \pi \neq \geq \leq \\ \left \{ {{y=2} \atop {x=2}} \right. \int\limits^a_b {x} \, dx x^{2} \sqrt{x} \sqrt{x} \\

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Write the balanced standard combustion reaction for the c5h7on3s2
AlexFokin [52]

Answer:

4C5H7ON3S2 + 25O2 —> 20CO2 + 14H2O + 6N2 + 4S2

Explanation:

When C5H7ON3S2 under go Combustion, the following are obtained as illustrated below:

C5H7ON3S2 + O2 —> CO2 + H2O + N2 + S2

Now, let us balance the equation. This is illustrated below:

C5H7ON3S2 + O2 —> CO2 + H2O + N2 + S2

There are 3 atoms of N on the left side and 2 atoms on the right side. It can be balance by putting 4 in front of C5H7ON3S2 and 6 in front of N2 as shown below:

4C5H7ON3S2 + O2 —> CO2 + H2O + 6N2 + S2

There are 20 atoms of C on the left side and 1 atom on the right side. It can be balance by putting 20 in front of CO2 as shown below:

4C5H7ON3S2 + O2 —> 20CO2 + H2O + 6N2 + S2

There are 28 atoms on H on the left side and 2 atoms on the right side. It can be balance by putting 14 in front of H2O as shown below:

4C5H7ON3S2 + O2 —> 20CO2 + 14H2O + 6N2 + S2

There are 8 atoms of S on the left side and 2 atoms on the right side. It can be balance by putting 4 in front of S2 as shown below:

4C5H7ON3S2 + O2 —> 20CO2 + 14H2O + 6N2 + 4S2

Now, there are a total of 54 atoms of O on the right side and 6 atoms on the left side

It can be balance by putting 25 in front of O2 as shown below:

4C5H7ON3S2 + 25O2 —> 20CO2 + 14H2O + 6N2 + 4S2

Now, we can see that the equation is balanced.

4 0
2 years ago
Which is common to the life cycles of both flowering and non-flowering plants?
Stolb23 [73]

Answer:

2 stay dormant

bbdndndn

4 0
3 years ago
Read 2 more answers
A sample of 450.0 g of water is found to contain 180 mg Cd. What is this concentration in parts per million?
navik [9.2K]

Answer:

The correct answer is 399.8 ppm

Explanation:

A concentration in parts per million (ppm) is equal to:

1 ppm = \frac{1 g solute}{10^{6}g solution}= \frac{1 mg solute}{1 kg solution}

Solute: Cd; Mass = 180 mg x (1 g/1000 mg) = 0.18 g

Solvent: Water ; Mass= 450.0 g x (1 kg/1000 g) = 0.45 kg

We have the following total mass of solution:

Mass of solution = Mass of solute + Mass of solvent = 0.18 g + 450 g = 450.18 g = 0.45018 kg

Finally, we divide the <u>mass of solute (in mg)</u> into the <u>mass of solution (in kg)</u> to obtain the ppm (in mg/Kg):

ppm = 180 mg/0.45018 kg = 399.8 mg/Kg = 399.8 ppm

4 0
3 years ago
A(n) ____________________ is a compound that turns litmus blue and is often found in soaps and detergents. a. acid b. base
steposvetlana [31]
A base is a <span>compound that turns litmus blue and is often found in soaps and detergents. Laundry detergent and dish soap contain bases.</span>
3 0
3 years ago
Read 2 more answers
Please help me please
Roman55 [17]

Answer:

Explanation:

Molarity = moles / volume (L)

moles = mass (g) / Molecular weight (g/mol)

so you have mass in gram and volume in ml ( Volume must be in litter because unit of mass is gram )

g = L     ,   mg = ml

first you must calculate the number of moles for each molecule and convert the ml to L and use the molarity law to calculate molarity for each molecule .

Ex71.

a.   Mw for NaCl = 23+35 = 58 g/mole

no of moles = 1.5 / 58 = 0.025

ml to L = 100/1000 = 0.1 L

Molarity = 0.025 / 0.1 = 0.25 M

b. Mw for K2CrO4 = 39x2 + 52 + 16x4 = 194 g/mol

no of moles = 1.5 / 194 = 0.0077

ml to L = 100 / 1000 = 0.1 L

Molarity = 0.0077 / 0.1 = 0.077 M

----------------------------------------------

Ex 72

a.  Mw for MgBr = 24 + 80 = 104 g/mol

no of moles = 20 / 104 = 0.19

ml to L = 250 / 1000 = 0.25 L

Molarity = 0.19 / 0.25 = 0.76 M

b. Mw for LiCO = 7 + 12 + 16 = 35 g/mol

no of moles = 5.55 / 35 = 0.158 moles

ml to L = 75 / 1000 = 0.075 L

Molarity = 0.158 / 0.075 = 2.106 M

Good Luck

3 0
3 years ago
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