Answer:
![\rho =9g/mL](https://tex.z-dn.net/?f=%5Crho%20%3D9g%2FmL)
Explanation:
Hello,
In this case, since the density is computed via the division of the mass by the volume:
![\rho =\frac{m}{V}](https://tex.z-dn.net/?f=%5Crho%20%3D%5Cfrac%7Bm%7D%7BV%7D)
For the given mass of 54 g and volume of 6 mL, the density turns out:
![\rho =\frac{54g}{6mL}\\ \\\rho =9g/mL](https://tex.z-dn.net/?f=%5Crho%20%3D%5Cfrac%7B54g%7D%7B6mL%7D%5C%5C%20%5C%5C%5Crho%20%3D9g%2FmL)
Best regards.
It would be: c/∧ = 3*10^8 / 4.25*10^-11 = 7.05 * 10^18 /s...
Answer:
35.5450 will be rounded to 35.55
Explanation:
=35.5450
if the last digit is less than 5 then it will be ignored
=35.545
when the dropping digit is 5 then the retaining digit will increse by a factor of 1
=35.55
i hope this will help you
Answer:
Precise but not accurate.
Explanation:
We can tell the performance of the balance is precise, because the repeated measurements give values close to one another.
However, the performance of the balance is not accurate, as the mean value of the repeated measurements (195.587) is not close to the value considered as true (in this case the standard calibration mass with a certified value of 200.002 g).
Aluminium reacts with dilute sulfuric acid based on the following reaction:
<span>2Al + 3H2SO4 ..............> Al2 (SO4)3 + 3H2
From the periodic table:
mass of aluminium = 27 grams
mass of hydrogen = 1 gram
mass of oxygen = 16 grams
mass of sulfur = 32 grams
Therefore:
molar mass of aluminium = 27 grams
molar mass of sulfuric acid = 2(1) + 32 + 4(16) = 98 grams
From the balanced chemical equation:
2 moles of aluminium react with 3 moles of dilute sulfuric acid.
This means that 34 grams of Al react with 294 grams of the acid
To get the amount of aluminium that reacts with </span><span>5.890 g of sulfuric acid, we will do cross multiplication as follows:
</span>amount of Al = (<span>5.890 x 34) / 294 = 0.6811 grams</span>