Answer:
OPTION C is correct
C) 1.07 g
Explanation:
CaCl2(aq) + 2 AgNO3(aq) → 2 AgCl(s) + Ca(NO3)3(aq)
But we know molarity molarity= number of moles of solute/ volume of the solution
M= n/V
From the equation above
number of moles of Cacl2 = (37.5 ×0 .100 × 10^-3) = 0.00375 moles.
Then
1 mole of Cacl2 yields 2 moles of Agcl2
0.00375 moles of Cacl2 will produce let say Y.
Y= (0.00375 ×2)/1
= 0.0075 moles.
Number of moles of Agcl2 = mass /molar mass of Agcl
Molar mass of Agcl = 178
Then mass = 178 ×0.0075 = 1.047
Therefore, the mass of agcl precipitate is
1.07 g
Answer:
See Below for answer!
Explanation:
In order to find the number of orbitals given the principal quantum number, n, we can use 
. For example n=2 would have 8 orbitals.
A) 32
B) 98
C) 50
D) 18
Answer:
C is the correct answer
Explanation:
to test for the presence of carbonate minerals in a rock
I think number one is c not sure or not number 2 is C AND NUMBER 3 IS 1 Go with sliding friction number 2 go with rolling friction number 3 is static friction and 4 is force
