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ahrayia [7]
3 years ago
12

1) mechanical

Physics
1 answer:
Dafna1 [17]3 years ago
7 0
I am pretty sure about these answers.Thermal goes in the 4th blank.
Mechanical goes in the 2nd blank.
Electrical goes in the 3rd blank.
I think chemical goes in the 1st blank and light goes in the 5th blank
Hope this helps
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An object with a mass of 10 kg is accelerated upward at 2 m/sec2. What force is required?
telo118 [61]

Answer:

Answer: Given m = 10 kg and . F = 20 N. Thus, the force required to accelerate the object upward direction is 20 N.

Explanation:

Answer: Given m = 10 kg and . F = 20 N. Thus, the force required to accelerate the object upward direction is 20 N.

6 0
2 years ago
A 800hz tuning fork is vibrating, producing a sound wave in the air.
blsea [12.9K]

Answer:

The frequency of the sound wave is 800Hz

The speed of sound in a is about 340m/s.

Velocity = frequency x wavelength

making wavelength the subject formula

wavelength = Velocity/frequency.

wavelength = 340/800

wavelength = 0.425m.

3 0
2 years ago
The activity of a radioisotope is found to decrease 40% of its original value in 2.59 x 10 s.
Rainbow [258]

Answer: 0.0353\ s^{-1}

Explanation:

Given

Radioactive material is found to decrease 40% of its original value in 2.59\times 10\ s

Sample at any time is given by

N=N_oe^{-\lambda t}

where, \lambda=\text{decay constant}

Put values

\Rightarrow 0.4N_o=N_oe^{-\lambda\cdot 2.59\times 10}\\\Rightarrow 0.4=e^{-\lambda\cdot 2.59\times 10

Taking natural logarithm both side

\Rightarrow \lambda=\dfrac{\ln 2.5}{25.9}\\\\\Rightarrow \lambda =0.0353\ s^{-1}

8 0
3 years ago
According to Kepler's harmonic law, Neptune would have a _________ orbit around the Sun than Mercury.
chubhunter [2.5K]
Neptune would have a slower orbit i just did this

3 0
3 years ago
Read 2 more answers
A car moves forward up a hill at 12 m/s with a uniform backward acceleration of 1.6 m/s2. What is its displacement after 6 s?
Romashka [77]

Answer:

The displacement of the car after 6s is 43.2 m

Explanation:

Given;

velocity of the car, v = 12 m/s

acceleration of the car, a = -1.6 m/s² (backward acceleration)

time of motion, t = 6 s

The displacement of the car after 6s is given by the following kinematic equation;

d = ut + ¹/₂at²

d = (12 x 6) + ¹/₂(-1.6)(6)²

d = 72 - 28.8

d = 43.2 m

Therefore, the displacement of the car after 6s is 43.2 m

6 0
2 years ago
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