Given Information:
v = 3.5x10⁵ m/s
θ = 60°
Magnetic field = 0.60 T
no. of electrons = 6.242x10¹⁸
radius = 0.750 m
Required Information:
Magnetic force = F = ?
Magnetic field = B = ?
Answer:
Part A) F = 2.909x10⁻¹⁴ N
Part B) B = 5.34x10⁻⁷ T
Explanation:
Part A:
The magnetic force can be found using
F = qvBsin(θ)
Where q = 1.60x10⁻¹⁹ C and v is the speed of electron, B is the magnetic field and θ is the angle between v and B.
F = 1.60x10⁻¹⁹*3.5x10⁵*0.60sin(60°)
F = 2.909x10⁻¹⁴ N
Part B:
From the Ampere's law, the magnetic field can be found using
B = μ₀I/2πr
Where μ₀ = 4πx10⁻⁷ is the permeability of free space, I is the current, and B is the magnitude of the magnetic field produced.
1 ampere of current has 6.242x10¹⁸ electrons per second so
I = 1.25x10¹⁹/6.242x10¹⁸
I = 2.0032 A
B = 4πx10⁻⁷*2.0032/2π*0.750
B = 5.34x10⁻⁷ T
