Answer:
Time taken by the diameter droplet is 60 ns
Solution:
As per the question:
Diameter of the droplet, d = 1 mm = 0.001 m
Radius of the droplet, R = 0.0005 m
Time taken for complete evaporation, t = 1 min = 60 s
Diameter of the smaller droplet, d' =
Diameter of the smaller droplet, R' =
Now,
Volume of the droplet, V =
Volume of the smaller droplet, V' =
Volume of the droplet ∝ Time taken for complete evaporation
Thus
where
t' = taken taken by smaller droplet
t' =
Answer:
Below see details
Explanation:
A) It is attached. Please see the picture
B) First to calculate the overall mean,
μ=65∗25/75+80∗25/75+95∗25/75
μ=65∗25/75+80∗25/75+95∗25/75 = 80
Next to calculate E(MSTR) = σ2+(1/r−1) ∑ni(μi−μ)^2 = 5634
And E(MSE) = σ^2= 9
C) Yes, it is substantially large than E(MSE) in this case.
D) If we sampled 25 employees from each group, we are likely to get a F statistics to indicate differences of job satisfactions among three types of length of service of employees.
Answer:
#include <iostream>
#include <iomanip>
#include <string>
using namespace std;
int main() {
string name[5];
int age[5];
int i,j;
for ( i = 0; i<=4; i++ ) {
cout << "Please enter student's name:";
cin >> name[i];
cout << "Please enter student's age:";
cin >> age[i];
}
for (i=0;i<=4;i++){
cout<<"Age of "<< name[i]<<" is "<<age[i]<<endl;
}
}
Output of above program is displayed in figure attached.
