Answer:

Explanation:
Given that
Calorific value (CV) = 44 MJ/Kg
CV= 44,000 KJ/kg
Brake thermal efficiency(η) = 37.9 %
We know that

Where BP is the brake power



Brake specific fuel consumption (s)




Answer:
diameter is 14 mm
Explanation:
given data
power = 15 kW
rotation N = 1750 rpm
factor of safety = 3
to find out
minimum diameter
solution
we will apply here power formula to find T that is
power = 2π×N×T / 60 .................1
put here value
15 ×
= 2π×1750×T / 60
so
T = 81.84 Nm
and
torsion = T / Z ..........2
here Z is section modulus i.e = πd³/ 16
so from equation 2
torsion = 81.84 / πd³/ 16
so torsion = 416.75 / / d³ .................3
so from shear stress theory
torsion = σy / factor of safety
so here σy = 530 for 1020 steel
so
torsion = σy / factor of safety
416.75 / d³ = 530 ×
/ 3
so d = 0.0133 m
so diameter is 14 mm
Answer:
True.
Explanation:
There are two basic saw angles, and the little nob on the front controls the one angle, and the one on the rear controls the other.
Answer:
a)27.9%
b)
Explanation:
Given that
Fuel energy content = 73.1 MJ/kg
Useful power = 17.4 KW
Heat rejection rate = 44.8 KW
From first law of thermodynamics
Heat addition rate =Heat rejection rate + Power out put
Now by putting the values in the above formula
Heat addition rate = 44.8 + 17.4
Heat addition rate =62.2 KW
We know that efficiency is given as follows

So


So the efficiency is 27.9%.
Now to find usage rate of fuel
Lets take usage rate is 
Fuel energy content x usage rate of fuel = Heat addition rate
Now by putting the values

