Assume that acid rain has lowered the ph of a particular lake to ph 5.0. what is the hydroxide ion concentration of this lake?
1 answer:
That acid rain has lowered the ph of a particular lake to ph 5.0. the hydroxide ion concentration of this lake is
1 × 10^-9 mol of hydroxide ions per liter of lake water
pH + pOH = 14
pOH = 14 - 5
pOH = 9.00
pOH = -log [OH⁻]
[OH⁻] = 10^-pOH
[OH⁻] = mol
Therefore,
the hydroxide ion concentration of this lake is 1 × 10^-9 mol
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<u>Answer:</u> The value of for the surrounding when given amount of HCl gas is reacted is 73.21 J/K
<u>Explanation:</u>
Entropy change is defined as the difference in entropy of all the product and the reactants each multiplied with their respective number of moles.
The equation used to calculate entropy change is of a reaction is:
For the given chemical reaction:
The equation for the entropy change of the above reaction is:
We are given:
Putting values in above equation, we get:
Entropy change of the surrounding = - (Entropy change of the system) = -(-129) J/K = 129 J/K
We are given:
Moles of HCl gas reacted = 2.27 moles
By Stoichiometry of the reaction:
When 4 mole of HCl gas is reacted, the entropy change of the surrounding will be 129 J/K
So, when 2.27 moles of HCl gas is reacted, the entropy change of the surrounding will be =
Hence, the value of for the surrounding when given amount of HCl gas is reacted is 73.21 J/K