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3 years ago

10

Imagine a sound wave with a frequency of 1 kHz propagating with a speed of 1500 m/s in water. Determine the phase difference in

radians between any two points on the wave separated by 5 cm.

1 answer:

spin [16.1K]3 years ago

6 0

Answer:

Phase difference will be equal to $\frac{\pi }{15}radian$

Explanation:

We have given frequency f = 1 kHz

Velocity of sound wave v = 1500 m/sec

It is given that wave are separated by 5 cm

So d = 0.05 m

We know that velocity is equal to $v=\lambda f$ , here $\lambda$ is wavelength and f is frequency

So $\lambda =\frac{v}{f}=\frac{1500}{1000}=1.5m$

$\beta$ is equal to $\beta =\frac{2\pi }{\lambda }=\frac{2\times 3.14}{1.5}=\frac{4\pi }{3}rad/m$

Phase difference is equal to $\Phi =\beta d=\frac{4\pi }{3}\times 0.05=\frac{\pi }{15}radian$

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When flying the LNAV approach, the missed approach point (MAP) would be indicated by reaching __________. A. an altitude of 3100

frutty [35]

Answer:

When flying the LNAV Approach, the missed approach point (MAP) would be indicated by reaching:

C. the RW30 waypoint.

Explanation:

In Aviation, LNAV stands for Lateral Navigation. The option a is incorrect as an altitude of 3100 feet refers to the decision altitude not the missed approach point.
The option b is incorrect as a distance of 1.5 NM to RW30 referring to the Visual descent point (VDP) is 1.5 nautical miles for the Runway (RW) 30 from threshold.
The option c is correct as Missed approach point is designed to coincide with the runway threshold. The RW 30 way point is referring to the way point to the threshold for the Runway 30.

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3 years ago

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Tems11 [23]

Answer:

Evaporation

Explanation:

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3 years ago

After getting a haircut, Joey’s barber spins him around in his barber’s chair 2 times per second. Is period or frequency given?

Rzqust [24]

Answer:

Explanation:

This figure given is the frequency; 2 times per second represents frequency.

What is frequency?

It is the number of times per seconds something goes past or around another.

it is expressed as:

Frequency = $\frac{n}{t}$

where n is the number of turns

t is the time taken

Therefore, the Barber spinned him 2 times in 1 second.

The period is the inverse of frequency. It is the time taken for a body to go through a point;

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3 years ago

A single circular loop of wire of radius 0.75 m carries a constant current of 3.0 A. The loop may be rotated about an axis that

NISA [10]

Answer:

B = 0.8 T

Explanation:

It is given that,

Radius of circular loop, r = 0.75 m

Current in the loop, I = 3 A

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When the orientation of the normal to the loop with respect to the direction of the magnetic field is 25°, the torque on the coil is 1.8 Nm.

We need to find the magnitude of the uniform magnetic field exerting this torque on the loop. Torque acting on the loop is given by :

$\tau=NIAB\sin\theta$

B is magnetic field

$B=\dfrac{\tau}{NIA\sin\theta}\\\\B=\dfrac{1.8}{1\times \pi \times (0.75)^2\times 3\times \sin(25)}\\\\B=0.8\ T$

So, the magnitude of the uniform magnetic field exerting this torque on the loop is 0.8 T.

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3 years ago

A visible light has a wavelength of 727.3 nm. Determine its frequency, energy per photon, and color.

Snezhnost [94]

Answer:

$f=4.12\times 10^{14}\ Hz$ and $E=2.73\times 10^{-19}\ J$

Explanation:

The wavelength of a visible light is 727.3 nm.

$727.3\ nm=727.3 \times 10^{-9}\ m$

The formula is as follows :

$c=f\lambda$

f is the frequency of the visible light

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Energy of a photon is given by :

E = hf, h is Planck's constant

$E=6.63\times 10^{-34}\times 4.12\times 10^{14}\\\\E=2.73\times 10^{-19}\ J$

Red color has a frequency of $4.12\times 10^{14}\ Hz$ and energy per photon is $2.73\times 10^{-19}\ J$ .

3 0

3 years ago