Question

Imagine a sound wave with a frequency of 1 kHz propagating with a speed of 1500 m/s in water. Determine the phase difference in radians between any two points on the wave separated by 5 cm.

Answer 1

Answer:

Phase difference will be equal to $\frac{\pi }{15}radian$

Explanation:

We have given frequency f = 1 kHz

Velocity of sound wave v = 1500 m/sec

It is given that wave are separated by 5 cm

So d = 0.05 m

We know that velocity is equal to $v=\lambda f$, here $\lambda$ is wavelength and f is frequency

So $\lambda =\frac{v}{f}=\frac{1500}{1000}=1.5m$

$\beta$  is equal to $\beta =\frac{2\pi }{\lambda }=\frac{2\times 3.14}{1.5}=\frac{4\pi }{3}rad/m$

Phase difference is equal to $\Phi =\beta d=\frac{4\pi }{3}\times 0.05=\frac{\pi }{15}radian$