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yarga [219]
3 years ago
10

Imagine a sound wave with a frequency of 1 kHz propagating with a speed of 1500 m/s in water. Determine the phase difference in

radians between any two points on the wave separated by 5 cm.
Physics
1 answer:
spin [16.1K]3 years ago
6 0

Answer:

Phase difference will be equal to \frac{\pi }{15}radian

Explanation:

We have given frequency f = 1 kHz

Velocity of sound wave v = 1500 m/sec

It is given that wave are separated by 5 cm

So d = 0.05 m

We know that velocity is equal to v=\lambda f, here \lambda is wavelength and f is frequency

So \lambda =\frac{v}{f}=\frac{1500}{1000}=1.5m

\beta  is equal to \beta =\frac{2\pi }{\lambda }=\frac{2\times 3.14}{1.5}=\frac{4\pi }{3}rad/m

Phase difference is equal to \Phi =\beta d=\frac{4\pi }{3}\times 0.05=\frac{\pi }{15}radian

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